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Wewaii [24]
4 years ago
6

125 A football stadium holds 55,296 people. The seating is divided into

Mathematics
1 answer:
stiks02 [169]4 years ago
4 0

Answer:

1536

Step-by-step explanation:

simply divide 55296 by 36

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X=2y-4<br>7x+5y=-66 <br> what is the x- value​
Gwar [14]

Answer:

x = -8

Step-by-step explanation:

x = 2y - 4 --- Equation 1

7x + 5y = -66 --- Equation 2

I will be using the substitution method to solve this.

Substitute x = 2y - 4 into Equation 2:

7x + 5y = -66

7(2y - 4) + 5y = -66

Evaluate.

14y - 28 + 5y = -66

Evaluate like terms.

19y - 28 = -66

Isolate 19y.

19y = -66 + 28

     = -38

Find y.

y = -38 ÷ 19

y = -2 --- Equation 3

Substitute y = -2 into Equation 1:

x = 2y - 4

x = 2(-2) - 4

Evaluate.

x = -4 - 4

x = -8

5 0
3 years ago
Will mark brainliest :) Given vectors u = -9i + 8j and v = 7i + 5j find 2u -6j in terms of unit vectors i and j
a_sh-v [17]

Answer:

b.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Express -2(x - y) -10 = 0 in standard form.
goldenfox [79]

Answer:

2x - 2y = - 10

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

- 2(x - y) - 10 = 0 ← distribute parenthesis on left side

- 2x + 2y - 10 = 0 ( add 10 to both sides )

- 2x + 2y = 10 ( multiply through by - 1 )

2x - 2y = - 10 ← in standard form

8 0
3 years ago
Commemorative coins come in packs of 15,while coin holders come in packs of 25. What are the least numbers of packs you should b
kozerog [31]
The least common multiple of 25 and 15 is 75. You'd do _ x 25 = 75 and _ x 15 = 75. The answer would be 3 and 5, so 5 packs of coins and 3 packs of coin holders.
7 0
3 years ago
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If an object has a mass of 12Kg on Earth, what would its mass be on the Moon and Mars?
Leviafan [203]

Answer:

mars = 4.54 kg and moon = 1.98 kg

Step-by-step explanation:

12 kg on mars =  4.54 kg

12 kg on moon =  1.98 kg

6 0
3 years ago
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