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o-na [289]
3 years ago
15

Solve the equation algebraically. x^2-7x-1/7=0

Mathematics
1 answer:
valentina_108 [34]3 years ago
7 0

Answer:

x1=\frac{49+\sqrt{2429}}{14} \\x2=\frac{49-\sqrt{2429}}{14} \\

Step-by-step explanation:

x^2-7x-\frac{1}{7} =0\\7x^2-49x-1=0\\D=b^2-4ac=(-49)^2-4*7*(-1)=2429\\x1=\frac{49+\sqrt{2429} }{14} \\x2=\frac{49-\sqrt{2429} }{14} \\

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Answer:

y= -16

Step-by-step explanation:

Y= -3x - 1

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3 years ago
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Lelu [443]

Answer/Step-by-step explanation:

Let's solve your equation step-by-step.

4−(2y+5)=3(1−4y)

Step 1: Simplify both sides of the equation.

4−(2y+5)=3(1−4y)

4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)

4+−1(2y)+(−1)(5)=3(1−4y)

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4+−2y+−5=3+−12y

(−2y)+(4+−5)=−12y+3(Combine Like Terms)

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Step 2: Add 12y to both sides.

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Step 3: Add 1 to both sides.

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Step-by-step explanation:

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