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never [62]
3 years ago
5

What is the area of the rectangle whose length is (x + 5) and width (x-5)​

Mathematics
2 answers:
Vinvika [58]3 years ago
7 0

Answer:

area of the rectangle is length *breadth

length =(x+5)

breadth =(x-5)

=(x+5)(x-5)=x^2-5x+5x-25=x^2-25

Helen [10]3 years ago
4 0

Answer:

\boxed {\boxed {\sf a=x^2-25}}

Step-by-step explanation:

The area of a rectangle is the product of length and width.

a=l*w

The length is (x+5) and the width is (x-5).

a= (x+5)(x-5)

We have two binominals, so we can multiply using FOIL: First, Outside, Inside, Last.

  • F: x*x= x²
  • O: x*-5= -5x
  • I: x*5= 5x
  • L: 5*-5 = -25

a= x^2-5x+5x-25

Combine the like terms: -5x and 5x. They cancel each other out.

a=x^2-25

The area of the rectangle is <u>x²-25</u>

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