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qwelly [4]
3 years ago
11

T is the midpoint of PQ. PT = (6x-3) and QT = (2x+5)

Mathematics
2 answers:
weeeeeb [17]3 years ago
7 0

Answer:

Question 1091219: T is the midpoint of PQ PT=6x+5 a. Find the value of x. TQ=8x-6 b. Find PT, TQ, and PQ. Answer by greenestamps(7331) (Show Source): You can put this solution on YOUR website! If T is the midpoint of PQ, then PT = TQ.

Step-by-step explanation:

adoni [48]3 years ago
3 0

Answer:

PQ = 8x + 2

Step-by-step explanation:

Since, T is the midpoint of PQ.

Therefore,

PQ = PT + QT

= (6x - 3) + (2x + 5)

= 6x + 2x + 5-3

PQ = 8x + 2

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70 - 5x = number of people waiting in line to buy tickets x minutes after a ticket booth opened is given by 70 - 5x. What does t
Snowcat [4.5K]

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The 70 represents the number of people waiting to by tickets at the exactly moment when the ticket booth is opened.

Step-by-step explanation:

The 70 represents the number of people waiting to by tickets at the exactly moment when the ticket booth is opened.

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4 0
3 years ago
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

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3 years ago
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Answer:

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