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Veseljchak [2.6K]
3 years ago
13

Determine the greatest intergral value of K for which 2x^2 - Kx +2 =0 will have non-real roots ...Use quadratic inequalities to

determine the solution
Mathematics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

Greatest integral value of K = 3.

Step-by-step explanation:

The nature of the roots of a quadratic equation is determined by the sign of the discriminant, b^2 - 4ac.  For non-real roots this is negative.

2x^2 - kx + 9 = 0

The discriminant = (-k)^2 - 4*2*2 , so:

k^2 - 16 < 0  for non-real roots.

k^2 < 16

k <  √16

k  < 4

So the answer is 3.

The greatest integral value is 8.

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-5(w+4) +8&lt; - 42 need a quick answer
Nesterboy [21]

Answer:

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Step-by-step explanation:

Let's solve your inequality step-by-step.

−5(w+4)+8<−42

Step 1: Simplify both sides of the inequality.

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Step 2: Add 12 to both sides.

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Step 3: Divide both sides by -5.

\frac{-5w}{-5} < \frac{-30}{-5}

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<u>Answer: </u>

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Lets plug in the answer choices and see which one works

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B. x = -5

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True, so C is the answer.

But lets just check D to make sure C is the answer.

D. x = 2

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False, so D isn't the answer either.


C is your answer :)
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Answer:

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Step-by-step explanation:


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