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kvv77 [185]
3 years ago
11

One hypotenuse and one leg of a right triangle have lengths 61 and 11. Find the length of the other leg

Mathematics
1 answer:
atroni [7]3 years ago
5 0
If the length is the same as one leg, than all the other legs should be the same exact dimensions, legs can not be different measurements by height. Hope that this help you!
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In the square below, the two semi-circles are congruent. Find the area of the shaded region. If necessary, round your answer to
Jobisdone [24]
Let's start with the area of the square
area \: square = s \times s = 8 \times 8 = 64
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

area \: circle = \pi {r}^{2}  = \pi \times  {4}^{2}  = 16\pi
now we just subtract and our answer is

64 - 16\pi = 64 - 16 \times (3.14) = 13.73
3 0
3 years ago
(08.01 MC)
Colt1911 [192]

Part A:

We see that this pair of equations has 1 solution. On a graph, the solutions of 2 (or more) lines is where the lines intersect. In this case, since these lines intersect 1 time, they have 1 solution.

Part B:

As previously mentioned, the solutions of multiple lines is where the lines intersect. In this case, since they intersect at (4,4), that is the solution.

6 0
3 years ago
Please help I am confused.
nignag [31]

Answer:

9 cm, C

11 cm, B

14 cm A

Step-by-step explanation:

7 0
2 years ago
Help....................................DDDDDDDDDDDDDDDDDDDDDDDDDDD
m_a_m_a [10]

Answer:

Step-by-step explanation:

a). Since, ΔABC ~ ΔWYZ

Their corresponding sides will be proportional.

\frac{AB}{WY}=\frac{BC}{YZ}= \frac{AC}{WZ}

\frac{194}{WY}=\frac{BC}{1}= \frac{130}{WZ}  --------(1)

By applying Pythagoras theorem in ΔABC,

AB² = AC² + BC²

BC² = AB² - AC²

BC² = (194)² - (130)²

BC² = 20736

BC = 144

From equation (1)

\frac{194}{WY}=\frac{144}{1}= \frac{130}{WZ}

\frac{194}{WY}=\frac{144}{1}

WY = \frac{194}{144}

WY = \frac{97}{72} = 1.35

\frac{144}{1}= \frac{130}{WZ}

WZ = \frac{130}{144}

WZ = \frac{65}{72} = 0.90

b). tan(A) = \frac{\text{Opposite side}}{\text{Adjacent side}}

               = \frac{144}{130}

               = \frac{72}{65}

Since, ΔABC ~ ΔWYZ,

∠A ≅ ∠W

Therefore, tangent of angle A and angle W will measure \frac{72}{65}.

8 0
3 years ago
Enter the range of data 37,45,20,34,28,80
Montano1993 [528]

Answer:

60

Step-by-step explanation:

To find the range, you subtract the largest number and the smallest number.

Largest number: 80

Smallest number: 20

80-20=60

8 0
3 years ago
Read 2 more answers
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