Answer:
90 degrees F
Step-by-step explanation:
if the distance from the temperatures is 26 degrees and the low point is 64, just add up 26 and 64 and you will get 90 degrees F.
Answer:
i) 1350 m
ii) 5400 m
Step-by-step explanation:
<u>Formula for Speed</u>

Rearrange the formula so that Distance is the subject:

<h3><u>Question (i)</u></h3>
Given:
- Speed = 45 m/s (meters per second)
- Time = 30 seconds
Substitute the given values into the formula for distance:

<h3><u>Question (ii)</u></h3>
Given:
- Speed = 45 m/s (meters per second)
- Time = 2 minutes
As the time is given in a different unit of time as the speed, we must first convert the time into seconds:
1 minute = 60 seconds
⇒ 2 minutes = 60 × 2 = 120 seconds
Therefore:
- Speed = 45 m/s (meters per second)
- Time = 120 seconds
Substitute the values into the formula for distance:

Answer:
What kind of problem? Multiplication? Division? What?
Step-by-step explanation:
Answer:
The length of the line segment UV is 76 units
Step-by-step explanation:
In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length
In Δ ONT
∵ U is the mid-point of ON
∵ V is the mid-point of TN
→ That means UV is joining the mid-points of two sides
∴ UV // OT
∴ UV =
OT
∵ UV = 7x - 8
∵ OT = 12x + 8
∴ 7x - 8 =
(12x + 8)
→ Multiply the bracket by 
∵
(12x + 8) =
(12x) +
(8) = 6x + 4
∴ 7x - 8 = 6x + 4
→ Add 8 to both sides
∴ 7x - 8 + 8 = 6x + 4 + 8
∴ 7x = 6x + 12
→ Subtract 6x from both sides
∴ 7x - 6x = 6x - 6x + 12
∴ x = 12
→ Substitute the value of x in the expression of UV to find it
∵ UV = 7(12) - 8 = 84 - 8
∴ UV = 76
∴ The length of the line segment UV is 76 units
The parametric equations for x and y describe a circle of radius 10 m, so the length of the base of the fence is the length of the circumference of a circle of radius 10 m. The formula for that circumference (C) is ...
... C = 2πr
... C = 2π·(10 m) = 20π m
The height as a function of angle (t) is found by substituting for x and y.
... h(t) = h(x(t), y(t)) = 4 + 0.01·((10cos(t))²-)10sin(t))²) = 4+cos(2t)
The average value of this over the range 0 ≤ t ≤ 2π is 4, since the cosine function has two full cycles in that range, and its average value over a cycle is zero.
Thus, the area of one side of the fence is that of a rectangle 20π m long and 4 m wide. That will be
... (20π m)·(4 m) = 80π m²
The amount of paint required to cover both sides of the fence is
... 2×(80π m²)×(1 L)/(10 m²) = 16π L ≈ 50.3 L
_____
You can work out the integral for area as a function of t. When you do, you will find it gives this same result.