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GrogVix [38]
3 years ago
12

A=6,b=8 the length of the hypotenuse c is

Mathematics
1 answer:
german3 years ago
6 0

Answer:

100 or 10²

Step-by-step explanation:

First, for this kind of question, we will use the Pythagorean theorem.

a² + b² = c²

--> 6² + 8² = 10²

----> 36 + 64 = 100

------> The length of hypotenuse c is 100

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Two is equal to 4 less than 3 times a certain number. Find the number.
Allushta [10]

Answer:

2

Step-by-step explanation:

2=3x-4

6=3x

x=2

5 0
3 years ago
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Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!
inn [45]

Answer:

economy class = 260

business class = 100.

Step-by-step explanation:

for every 13 economy seats, there are 5 business class seats

EC = 13

BC = 5

ADD  to get total = 18

divide 360 by 18 to get the number of groups created.

you get 20.

multiply 20 by each class seats

13 by 20 = 260

5 by 20 = 100

you can confirm by adding the seats to see if you will get 360.

5 0
3 years ago
nora is planning a birthday party for her little sister, colleen. she needs to purchase 12 cupcakes she can not spend more than
Lapatulllka [165]

Answer:

if she cannot spend more than $40, she will spend .3 on each cupcake

Step-by-step explanation:

when you divide 12 by 40, you get .3 and to check if it is true, you can multiply .3 x 40 and you will get 12 hope you get it right, and have a good day :)

6 0
3 years ago
Find a ratio equivalent to 8/3. Then, use te ratios to write a proportion
Galina-37 [17]
A ratio that is equivalent to 8/3 is 16/6.

Because:-  8*2= 16
                  3*2=6

16/6 is equivalent to 8/3

Writing a proportion:-

8/3=16/6
8 0
3 years ago
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Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA
AleksAgata [21]

1. Start with ΔCIJ.

  • ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
  • the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
  • ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

  • ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
  • ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
  • the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
  • ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.

4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

5. ΔABC is isosceles, then angles adjacent to the base are congruent:

m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

-x=-17°,

x=17°.

Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

3 0
3 years ago
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