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3 years ago

8

Each morning you feed your dog 2525 cup of dry dog food. At night, you feed him 1212 cup of dry dog food. You buy a bag of dog f

ood that contains 1818 cups. How many days will the bag last?

1 answer:

MAVERICK [17]3 years ago

3 0

Answer:

It will last 0 days. You will need more than 1 bag.

Step-by-step explanation:

25 cups + 12 cups = 37 cups

37 cups is a little more than 2 times the amount of cups in 1 bag.

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Classify the expression: −2x

ValentinkaMS [17]

Answer:

classical music

Step-by-step explanation:

i suggest beetoven for classicla and for rock the rock

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3 years ago

List the next four multiples of the unit fraction 1/5,

svetoff [14.1K]

Next multiples of the unit fraction 1/5 are
2/5
3/5
4/5
5/5 = 1

Hope this helps.. :)

6 0

3 years ago

Round off 787592799 to the nearest 10

timama [110]

Answer:

787592800

Step-by-step explanation:

Hi there,

If you round this answer to the nearest tens place, it would be 787592800. Since the 799 is closer to 800 rather than 790, it would round up and change the last three digits of the number instead of the usual two digits.

Hope this answer helps. Cheers.

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3 years ago

If the square root of x is greater than x then x could be

Shtirlitz [24]

Any decimal under 1, i believe.

8 0

4 years ago

Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand

kvasek [131]

Answer:

(a) $\frac{5}{7},\frac{1}{6}$ (b) $\frac{1}{7},\frac{1}{6}$ (c) $\frac{5}{7},\frac{2}{3},\frac{3}{5}$

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with $5$ blue marbles, $1$ white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag $=7$

(a)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(b)

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{7}$

As marble is not returned to bag,

Probability of drawing white marble $=\frac{\text{total white marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(c)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing second blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{4}{6}=\frac{2}{3}$

As marble is not returned to the bag

Probability of drawing third blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{3}{5}$

8 0

3 years ago