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Basile [38]
2 years ago
8

Each morning you feed your dog 2525 cup of dry dog food. At night, you feed him 1212 cup of dry dog food. You buy a bag of dog f

ood that contains 1818 cups. How many days will the bag last?
Mathematics
1 answer:
MAVERICK [17]2 years ago
3 0

Answer:

It will last 0 days. You will need more than 1 bag.

Step-by-step explanation:

25 cups + 12 cups = 37 cups

37 cups is a little more than 2 times the amount of cups in 1 bag.

You might be interested in
(2, 4) and (6, 12) find slope
Free_Kalibri [48]

Answer:

2

Step-by-step explanation:

Use the formula: change of y over change of x.

When you do that, your systems should look like this:

x1 = 2

y1 = 4

x2 = 6

y2 = 12

After that you plug these number into the corresponding variable.

(12 - 4) / (6 - 2) = 8/4 which equals 2.

4 0
3 years ago
Find the area of the figure shown. Use 3.14 to approximate pi
Nina [5.8K]
Alrighty

we gots 1/4 circle and paralellogram

area circle=pi times radius^2
area paralelogram=base times height


1/4 circle is
radius is 10 so
area part circle is 1/4 times pi times 10^2=100/4pi=25pi=78.5 m²

area paralllogram is
10 times 3 because 3 is height and 10 is base length or 30

30+78.5=108.5 m² is the area
4 0
3 years ago
The perimeter of a square is 48 feet. What is the length of a side?
Anettt [7]
12ft (48 divided by 4)
4 0
3 years ago
Correlation coefficients fall in a scale from -1.0 to 1.0 and show how ________ the points are on the scatter plot around a ____
Shkiper50 [21]
Did they give multiple Choice
7 0
3 years ago
The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 36}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0
3 years ago
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