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quester [9]
3 years ago
9

Design and implement an application that reads a sequence of up to 25 pairs of names and postal (ZIP) codes for individuals. Sto

re the data in an object designed to store a first name (string), last name (string), and postal code (integer). Assume each line of input will contain two strings followed by an integer value, each separated by a tab character. Then, after the input has been read in, print the list in an appropriate format to the screen.
Computers and Technology
1 answer:
Vikki [24]3 years ago
3 0

Answer:

Kindly go to the explanation for the answer.

Explanation:

Person.java

public class Person{

private String firstName, lastName;

private int zip;

public Person(String firstName, String lastName, int zip) {

super();

this.firstName = firstName;

this.lastName = lastName;

this.zip = zip;

}

public String toString() {

String line = "\tFirst Name = " + this.firstName + "\n\tLast Name = " + this.lastName;

line += "\n\tZip Code = " + this.zip + "\n";

return line;

}

}

Test.java

import java.util.ArrayList;

import java.util.Scanner;

public class Test{

public static void main(String args[]) {

Scanner in = new Scanner(System.in);

ArrayList<Person> al = new ArrayList<Person>();

for(int i = 0; i < 25; i++) {

System.out.print("Enter person details: ");

String line = in.nextLine();

String words[] = line.split("\t");

String fname = words[0];

String lname = words[1];

int numb = Integer.parseInt(words[2]);

Person p = new Person(fname, lname, numb);

al.add(p);

}

for(int i = 0; i < 25; i++) {

System.out.println("Person " + (i + 1) + ":");

System.out.println(al.get(i));

}

}

}

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2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

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So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

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Answer:

d. All of the above

Explanation:

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To send or receive data, the participating nodes in a Full Duplex system do not have to wait for a free carrier/medium. It employs a medium that has at least two internal channels - one for sending and one for receiving.

Based on the above explanations, options A, B and C are valid and are correct ways to accomplish full-duplex (FDX) digital communications on guided medium at the physical layer (OSI Layer 1). There all of them are correct.

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