Answer:
I KNOW I HAD IT BEFORE ITS C
Step-by-step explanation:
Answer:
See Below.
Step-by-step explanation:
We want to show that the function:

Increases for all values of <em>x</em>.
A function is increasing whenever its derivative is positive.
So, find the derivative of our function:
![\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5Be%5Ex%20-%20e%5E%7B-x%7D%5Cright%5D)
Differentiate:

Simplify:

Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>
Umm no you need to do your own work and do not be asking for answers
Nothing is handed to you ....you need to work HARD to get what you want.
Answer:
x^2+5x-14
Step-by-step explanation:
you multiply both equations so that you get:
x^2-2x+7x-14
and then you simplify it to:
x^2+5x-14
<em><u>If you found this helpful please give it a thanks </u></em>
<em><u>I would also appreciate it if you give me a brainliest</u></em>