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Morgarella [4.7K]
3 years ago
9

(30 points) algebra 1 PLZ HELP ASAP!!!!

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

u need 2 find the angles

Step-by-step explanation:

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Which expressions are equivalent to (5g+3h+4) •2
timama [110]

Step-by-step explanation:

Unfortunately you didn’t provide the expressions to chose from

however, we can write :

(5g+3h+4) •2 = 2*5g + 2*3h + 2*4  (using distributive property)

                     = 10g + 6h + 8.

5 0
3 years ago
I answered it but I just need someone to answer just to make sure mine are right
Artemon [7]
<h2>The missing measures of the angles are:</h2>

m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

<u>Given</u>:

m\angle Z = 138^{\circ}

<em><u>Note the following:</u></em>

  • An equilateral triangle has all its three angles equal to each other. Each angle = 60^{\circ}.
  • This implies that, since \triangle WXY is equilateral, therefore, m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}

  • Base angles of an isosceles triangle are congruent to each other.
  • This implies that, since \triangle WZY is isosceles, therefore, m\angle 3 = \angle 5

Applying the above stated, let's find the measure of each angle:

  • Find m\angle 1

m\angle 1 = 60^{\circ} (an angle in an equilateral triangle equals 60 degrees)

  • Find m\angle 2

m\angle 2 = 60 - m \angle 3

m\angle 2 = 60 -\frac{1}{2}(180 - 138) (Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)

m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}

  • Find m\angle 3 and m\angle 5 (base angles of isosceles triangle WZY)

m\angle 3 =  \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)

m\angle 3 =  \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}

m\angle3 = m\angle 5 (base angles of isosceles triangle are congruent)

Therefore,

m\angle5 = 21^{\circ}

  • Find m\angle 4

m\angle 4 = 60 - m\angle 5

Substitute

m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}

The missing measures of the angles are:

m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

Learn more here:

brainly.com/question/2944195

5 0
3 years ago
Expand. Your answer should be a polynomial in standard form. (6x+1)(1-3x)
Ludmilka [50]

Answer:

3x-18x^2+1

Step-by-step explanation:

(6x+1)(1-3x)

6x-18x^2+1-3x

6x-3x-18x^2+1

3x-18x^2+1

Hope this helps :)

3 0
3 years ago
Read 2 more answers
What best decribes the area of polygon
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Area is the space inside a shape
7 0
3 years ago
Help please asap algebra 2
timurjin [86]
X = approximately 633

Steps:
lnx + ln3x = 14

ln3x^2 = 14 : Use the log property of addition which is to multiply same log                           together so you multiply x and 3x because they have log in                                common

  (ln3x^2) =  (14)  : take base of e on both sides to get rid of the log
e                e

3x^2 = e^14  : e cancels out log on the left side and the right side is e^14 

x^2 = e^14 / 3 : divide both sides by 3

√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2                                  on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself

x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>

x = </span>633.141449221 : solve 
4 0
3 years ago
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