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astra-53 [7]
3 years ago
12

How would you solve #2 and #3?

Mathematics
1 answer:
nordsb [41]3 years ago
3 0
I think u just connect the lines
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IM SO LOST PLEASE HELP
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Check the picture below.

\bf \textit{lateral area of a cone}\\\\
LA=\pi r\stackrel{slant-height}{\sqrt{r^2+h^2}}~~
\begin{cases}
LA=539\pi \\
r=49
\end{cases}\implies 539\pi =\pi 49\sqrt{r^2+h^2}
\\\\\\
\cfrac{539\pi }{49\pi }=\sqrt{r^2+h^2}\implies 11=\sqrt{r^2+h^2}

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In x² , what is the 2 called?
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Answer:

<h2>an exponent</h2>

Step-by-step explanation:

In x², here the 2 is exponent while x is base.

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