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astra-53 [7]
3 years ago
12

How would you solve #2 and #3?

Mathematics
1 answer:
nordsb [41]3 years ago
3 0
I think u just connect the lines
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Dont guess!<br> I will mark brainliest if its correct!<br> Also no links!
GREYUIT [131]

Answer:

The correct answer will be; B or 40.

Step-by-step explanation:

Because when the ratio of boys changed from 8 to 32, it increased by "time 4" (8*4 = 32), so the same pattern will be followed for girls, multiplying the number that you already have by four; 10 (amount of girls given) * 4 = 40.

Hope this helped, Good Luck!

8 0
3 years ago
Read 2 more answers
• Machine s is cleaned every 12 weeks. •Machine that is cleaned every 8 weeks. What is the fewest number of weeks that will pass
vfiekz [6]
Week 24,assuming that both machines are cleaned at week 0, because multiples of 12 are 12, 24,36. And multiples of 8 are 8, 16, 24. 24 is also the LCM.
7 0
3 years ago
Bart's drive to the airport takes 232323 minutes. What is the latest time Bart can leave to arrive at the airport by a quarter b
Nikitich [7]
It take 23 mins for the drive

He needs to reach the airport by a quarter before 6

a quarter before 6 = 5.45
So he needs to leave 23 mins before 5.45

23 mins before 5.45 = 5.22
6 0
3 years ago
The length is _____ the width is______ and the area of the actual room is ___ _______
RSB [31]

Answer:

98 square inches.

Step-by-step explanation:

The length is 14 inches. The width is 7 inches.

7 * 14 = 98 square inches.

The area is 98 square inches.

8 0
3 years ago
For F(x)=2x+1 and G(x)=c^2-7 find (FxG)(x)
Ludmilka [50]

The value of F(G(x)) is 2x^2 - 13

<h3>How to solve the composite functions?</h3>

The functions are given as:

F(x)=2x+1

G(x)=x^2-7

To find (FxG)(x), we make use of

(FxG)(x) = F(G(x))

So, we have:

F(G(x))=2G(x)+1

Substitute G(x)=x^2-7

F(G(x))=2(x^2-7)+1

Expand

F(G(x))=2x^2 - 14 + 1

Evaluate the like terms

F(G(x))=2x^2 - 13

Hence, the value of F(G(x)) is 2x^2 - 13

Read more about composite functions at:

brainly.com/question/20379727

#SPJ1

4 0
2 years ago
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