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Serggg [28]
4 years ago
10

You have created a number of different documents using several applications including word, excel, and powerpoint. these files a

re located in different folders on your hard drive. you want to be able to access these folders from a single location without actually moving them from their current location. what feature of windows vista can you use?
Computers and Technology
1 answer:
hichkok12 [17]4 years ago
6 0
You can use <span>virtual folders.</span>
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The address space 0x0000-0x3FF is assigned to I/O peripherals of a given HCS12 chip. How many K bytes is this? (Points : 2) 2K
UNO [17]

Answer:

D. 1K

Explanation:

The address space 0x0000-0x3FF is of 1KB(One Kilo Byte) since 0x3ff is equal to 1023. therefore 1023=1 KB.

bitwise 0x3ff zeros out the top bits of the number such that the result is always between 0 and 1023. It is essentially the same thing as modulo( num,1024) for positive  values of num.

Hence the answer is D 1K

3 0
3 years ago
When should a writer establish common ground before the bottom-line statement? A. When the details are arranged in order of impo
BabaBlast [244]
In the bottom line statement,the writer can establish a common ground when b. the reader may disagree with the bottom line statement. Hope this is the best answer and would be of big help in this assignment of yours then.
3 0
3 years ago
Read 2 more answers
A Color class has three public, integer-returning accessor methods: getRed, getGreen, and getBlue, and three protected, void-ret
jek_recluse [69]

Answer:

The following code are:

public void dissolve() {

setRed(getRed()+1);

setGreen(getGreen()+1);

setBlue(getBlue()+1);

alpha+=1;

}

Explanation:

Here, we define the void type function "dissolve()" inside it, we set three function i.e, "setRed()", "setGreen()", "setBlue()" and then we increment the variable "alpha" by 1.

Inside those three mutators method we set three accessor methods i.e, "getRed()", "getGreen()" , "getBlue()" and increment these accessor by 1.

The values will not be returned by the mutator functions, the accessor will be returned the values.

6 0
3 years ago
Which of these sedimentary rocks is made of the largest particles?
Marta_Voda [28]
Your answer is <span>A.conglomerate.

Hope this helps :)</span>
6 0
4 years ago
Define an iterative function named append_ordered; it is passed two arguments: a linked list (ll) whose values are ordered from
enot [183]

Answer:

A python programming language (code) was used for this exercise.

The code is shown below in the explanation section

Explanation:

Solution

Python code:

class LN:

def __init__(self,value,next=None):

self.value = value

self.next = next

  def list_to_ll(self,l):

if l == []:

return None

front = rear = LN(l[0])

for v in l[1:]:

rear.next = LN(v)

rear = rear.next

return front

  def str_ll(self,ll):

answer = ''

while ll != None:

answer += str(ll.value)+'->'

ll = ll.next

return answer + 'None'

def append_ordered(self,ll,v):

ln1=LN(v); #create a node with the new value by creating an instance of the LN class

if ll is None: #if the linked list is empty

ll=ln1 #return the new created node

elif(ll.value >= ln1.value): #if the value to be add is smallest, append the linked list to it

ln1.next=ll

ll=ln1

else:

current=ll; #crate a temporary pointer to iterate over linked list

#iterate till the next node value is smaller than the new value and list is not over

while (current.next is not None and current.next.value < ln1.value):

current=current.next

ln1.next=current.next #save the current node in the next of the new node

current.next=ln1 #save new node in the next of current node

return ll

ln=LN(0); #create an instance of class LN

ll1=ln.list_to_ll([1,2,4,5]); #create a linked list of the list

answer=ln.str_ll(ll1);    

print(answer); #print the linked list

ll2=ln.append_ordered(ll1,3); #append the value 3 in the linked list

answer=ln.str_ll(ll2)

print(answer); #print the new linked list

Now,

  • If Linked list is empty then make the node as head and return it.
  • If value of the node to be inserted is smaller than value of head node, then insert the node at start and make it head.
  • In a loop, find the appropriate node after which the input node ( 10 ) is to be inserted.To find the appropriate node start from head,keep moving until you reach a node GN (12 ) who's value is greater than the input node. The node just before GN is the appropriate node (8).
  • Insert the node (10) after the appropriate node (8) found in step 3.

Note: Kindly find the output python code attached to the question below.

3 0
3 years ago
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