78 / 0.26 = 300 so the answer is 300
Answer:
-128 it’s on the table
Step-by-step explanation:
The result of the respective questions are:
- This chi-square test only takes into consideration one variable.
- The type of chi-square test this is is a Goodness of Fit
- df= 3
- NO
<h3>How many variables are involved in the chi-square test?</h3>
a)
This chi-square test only takes into consideration one variable.
b)
The type of chi-square test this is, is a Goodness of Fit
To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.
The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.
c)
Parameter
n = 4
Therefore
Degrees of freedom
df= n - 1
df= 4 - 1
df= 3
d)
In conclusion
Parameters

df = 3
Hence
Critical value = 7.814728
Test statistic = 6.6
Test statistic < Critical value, .
NO, the result of this test is not statistically significant.
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Answer:
The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 160 degrees
Standard Deviation, σ = 5.4 degrees
We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.2
Calculation the value from standard normal z table, we have,
Thus,

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.