Answer: 56 large cars and 86 small cars.
Step-by-step explanation:
Let's call:
: the number of large cars.
: the number of small cars.
Then, you can set up the following system of equations:
![\left \{ {{l+s=142} \atop {5.50l+4.0s=652.50}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bl%2Bs%3D142%7D%20%5Catop%20%7B5.50l%2B4.0s%3D652.50%7D%7D%20%5Cright.)
You can use the Elimination Method:
- Multiply the first equation by -4.0
- Add both equations.
- Solve for l.
![\left \{ {{-4.0l-4.0s=-568} \atop {5.50l+4.0s=652.50}} \right.\\--------\\1.5l=84.5](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B-4.0l-4.0s%3D-568%7D%20%5Catop%20%7B5.50l%2B4.0s%3D652.50%7D%7D%20%5Cright.%5C%5C--------%5C%5C1.5l%3D84.5)
≈![56](https://tex.z-dn.net/?f=56)
Substitute
into one of the original equations and solve for <em>s:</em>
<em> </em>![56+s=142\\s=142-56\\s=86](https://tex.z-dn.net/?f=56%2Bs%3D142%5C%5Cs%3D142-56%5C%5Cs%3D86)
Answer:
what method exactly r u using ????
Answer:
$172.80
Step-by-step explanation:
$160.00 x 1.08=$172.80
Answer:
Approximately 62 gallons of water will be used by Lee County by the year 2025.
Step-by-step explanation:
The amount, in millions gallons of water, spent by Lee County, in t years after 2019, is given by the following equation:
![P(t) = P(0)(1 + r)^{t}](https://tex.z-dn.net/?f=P%28t%29%20%3D%20P%280%29%281%20%2B%20r%29%5E%7Bt%7D)
In which P(0) is the amount spent on 2019 and r is the increse rate, as a decimal.
In the year 2019, Lee County used approximately 55 million gallons of water.
This means that ![P(0) = 55](https://tex.z-dn.net/?f=P%280%29%20%3D%2055)
Historical trends show that each year the water demand is increasing by a rate of approximately 2.1%.
This means that ![r = 0.021](https://tex.z-dn.net/?f=r%20%3D%200.021)
So
![P(t) = P(0)(1 + r)^{t}](https://tex.z-dn.net/?f=P%28t%29%20%3D%20P%280%29%281%20%2B%20r%29%5E%7Bt%7D)
![P(t) = 55(1 + 0.021)^{t}](https://tex.z-dn.net/?f=P%28t%29%20%3D%2055%281%20%2B%200.021%29%5E%7Bt%7D)
![P(t) = 55(1.021)^{t}](https://tex.z-dn.net/?f=P%28t%29%20%3D%2055%281.021%29%5E%7Bt%7D)
Approximately how many million gallons of water will be used by Lee County by the year 2025?
2025 is 2025 - 2019 = 6 years after 2019. So this is P(6).
![P(t) = 55(1.021)^{t}](https://tex.z-dn.net/?f=P%28t%29%20%3D%2055%281.021%29%5E%7Bt%7D)
![P(6) = 55(1.021)^{6}](https://tex.z-dn.net/?f=P%286%29%20%3D%2055%281.021%29%5E%7B6%7D)
![P(6) = 62.3](https://tex.z-dn.net/?f=P%286%29%20%3D%2062.3)
Rounded to the nearest millions
Approximately 62 gallons of water will be used by Lee County by the year 2025.
Hello,
(f-g)(x)=3x²+1-1+x=3x²+x
(f-g)(2)=3*2²+2=3*4+2=14