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tatuchka [14]
3 years ago
5

126/399 in simplest form?

Mathematics
2 answers:
Naddik [55]3 years ago
8 0

The answer to this question is 6/19.
Paha777 [63]3 years ago
3 0
Divide the top and bottom by the greatest common factor.  Well, I know both can be divided by 3.
126/3=42
399/3=133
So then you have 42/133
The top and bottom can then both be divided by 7.
42/7=6
133/7=19

So the answer is 6/19 or 0.315789
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What is hs the answer to this question?<br><br> Y= 5x+5<br> Y - x=5
ANEK [815]
Y = 5x + 5
y - x = 5

You can use substitution to solve this system. Use y's expression (5x + 5) for y in the second equation to solve for x:

y - x = 5
5x + 5 + x = 5
6x + 5 = 5
6x = 0
x = 0

Substitute your value for x into one of the original equations to y:

y = 5x + 5
y = 5(0) + 5
y = 5

Finally, substitute both values into both original equations to check your work:

5 = 5(0) + 5    -->    5 = 5    <--True
5 - 0 = 5    -->    5 = 5    <--True

Answer:
x = 0
y = 5
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3 years ago
In a survey, 60% of interviewees say they like beach sports, while 55% like mountain sports. If 20% like both, what fraction of
My name is Ann [436]

Answer:

0.05

Step-by-step explanation:

To solve this problem, we first need to calculate the percentage of people that like beach or mountain sports.

This percentage can be calculated with the formula:

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where:

P(M or M) is the percentage of people that like beach or mountain sports,

P(B) is the percentage of people that like beach sports,

P(M) is the percentage of people that like mountain sports,

P(B) is the percentage of people that like beach and mountain sports.

Then:

P(M or B) = 0.55 + 0.60 - 0.20 = 0.95

95% of the people like mountain or beach sport. Now, to find the percentage of people that like neither, we just need to make 1 minus the percentage of people that like beach or mountain sports:

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ArbitrLikvidat [17]

Answer:

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The constant is the part of the algebraic function or expression that does not change. In this case, as x changes, the constant -10 does not. Thus, -10 is the constant.

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nikdorinn [45]

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