Help me I am confused

Mathematics

1 answer:

Ratling [72]3 years ago

8 0

Answer:

x $\leq$ -6

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What are the coordinates of the point on the directed line segment from (- 3, - 9) to (4, 5) that partitions the segment into a

kompoz [17]

Answer:

(0,-1)

Step-by-step explanation:

Let the ends of the line segments be A(-4,3) and B(5,-6).

Ratio=4:5

By the concept of cordinate geometry,

x=(mx2+nx1)/(m+n)

y=(my2+ny1)/(m+n)

where m and n is the ratio m:n.

So, here the cordinates are

x={4(5)+5(-4)}/(4+5)

x=(20–20)/9

x=0

y={4(-6)+5(3)}/9

y={-24+15}/9

y=(-9)/9

y=(-1)

Therefore the cordinates of the point that divides the given line segment in the ratio 4 : 5 is (0,-1)

5 0

3 years ago

In △ABC the points M and N belong to the sides AC and AB respectively. AM= 1/3 AC, AN= 1/3 AB, BC=15. Find MN

Oliga [24]

$Answer: \\ We \: have \: \frac{AM}{AC} = \frac{1}{3} , \frac{AN}{AB} = \frac{1}{3} ,\hat{A} \: is \: a \: shared \: angle \\ \Rightarrow \bigtriangleup AMN \cong \bigtriangleup ACB \\ \Rightarrow MN = \frac{1}{3} BC = \frac{1}{3} \times 15 = 5$

8 0

3 years ago

A shipment of 40 fancy calculators contains 3 defective units. What is the probability if a college bookstore buys 20 calculator

JulsSmile [24]

Answer:

38.46%

Step-by-step explanation:

There are no names or marking that can make the calculator look different, so the order is not important. Then we should use a combination to solve this problem.

There are 40 calculators in one shipment, 37 of them good items and 3 of them are defect items. We need to choose 19 good calculators and 1 defect calculator. The number of ways to do that will be:

$\frac{37}{19}$ * $\frac{3}{1}$ = 37! $\frac{37!}{19!(37-19!)} * \frac{3!}{1!(3-1)!}$ = 53017895700