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SIZIF [17.4K]
3 years ago
5

How to solve 3sin^2x= cos^2x

Mathematics
1 answer:
DochEvi [55]3 years ago
7 0

I'll try it.
I just went through this twice on scratch paper.  The first time was to
see if I could do it, and the second time was because the first result
I got was ridiculous.  But I think I got it.

You said                                                 <span><u>3sin²(x) = cos²(x)</u>

Use this trig identity:  sin²(x) = 1 - cos²(x)   

                                   Plug it into the original equation for (x).

                                                     3(1 - cos²(x) )  =  cos²(x)

Remove parentheses on the left:    3 - 3cos²(x)  =  cos²(x)

Add  3cos²(x)  to each side:            3                  =  4cos²(x)

Divide each side by  4 :                  3/4  =  cos²(x)

Take the square root of each side:    <em>cos(x) = (√3) / 2</em> .

There it is ... the cosine of the unknown angle.
Now you just go look it up in a book with a table cosines,
or else pinch it through your computer or your calculator,
or else just remember that you've learned that

                           cos( <em><u>30°</u></em> )  =  </span><span><span>(√3) / 2 </span>.


</span>
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3 years ago
How to find the answers ?
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AD || BC and BD is the transversal,

Therefore, angle DBC = angle ADB = 42° [alternate angles]

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angle BAD + angle ABD + angle DBC = 180° [co-interior angles]

or, 106°+ angle ABD + 42° = 180°

or, 148° + angle ABD = 180°

or, angle ABD = 180°-148° = 32°

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or, 72+2x+12 = 180

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3 years ago
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3 years ago
GH bisects FGI. Find the measure of HGI<br><br> •15°<br> •21°<br> •10°<br> •8°
tester [92]

Answer:

m<HGI=21°

Step-by-step explanation:

we know that

If GH bisects m<FGI then

m<FGH=m<HGI

substitute the values

(2x+1)°=(3x-9)°

solve for x

3x-2x=1+9

x=10°

The measure of angle HGI is equal to

(3x-9)° ------> substitute the value of x

3*10-9=21°

m<HGI=21°

3 0
3 years ago
Read 2 more answers
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