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padilas [110]
3 years ago
8

How many pairs of whole numbers have a sum of 40

Mathematics
1 answer:
Ahat [919]3 years ago
3 0
It is 20 
39+1
38+2
37+3
36+4
35+5
<span>Until you get to 20+20</span>
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Pls dont guess on it
yuradex [85]

Answer:

2(8a + 8)

Step-by-step explanation:

The easiest way to do this is to substitute <em>a</em> for a number. For example, let's just make things easy and make <em>a </em> = 1.

So, if a = 1, the expression 16a + 8 would be 16(1) + 8 = 24.

Let's find all the expressions that would also equal 24 if <em>a = </em>24.

Plug in 1 for <em>a</em> in each of the equations. You will find that 2(8a + 8) will not equal 24 if <em>a </em>equals 1.

2(8a + 8)

2(8(1) + 8

2(8 + 8)

2(16)

32

4 0
2 years ago
Which comparison is NOT true?
HACTEHA [7]

Answer:

D

Step-by-step explanation:

Just look at the symbols lol

6 0
3 years ago
CAn yall help me with this ;-; im failing my math class and this will boost my grade
Tatiana [17]

Answer:

are there options if there are i can help

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Whats the value of the 2 in 0.812 and write the underline digit as a fraction.
Snowcat [4.5K]

Answer:

the value of 2 in 0.812 is 2 thousandths/0.002

0.002 = 2/1000

0.812 = 812/1000

3 0
3 years ago
Will Mark Brainlest help pleaseeeeee​
Masja [62]

Answer:

h(2) = 7/4

h(-3) = -2

h(-2) = 11/(-8)

h(-3) - h(-2) = -(5/8)

Step-by-step explanation:

h(x) = (2x^2-x+1) / (3x-2)

h(2) = (2*2^2 - 2 + 1) / (3*2 - 2)

       = (8 - 2 + 1) / (6 - 2)

       = 7/4

h(-3) = {2*(-3)^2 - (-3) + 1} / {3*(-3) - 2}

        = (18 + 3 + 1) / (-9 - 2)

        = 22/(-11)

        = -2

h(-2) = {2*(-2)^2 - (-2) + 1} / {3*(-2) - 2}

        = (8 + 2 + 1) / (-6 - 2)

        = 11/(-8)

h(-3) - h(-2) = (-2) - {11/(-8)}

                  = -(5/8)

Hope this will help. Please give me brainliest.

7 0
3 years ago
Read 2 more answers
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