Answer:
C. ± 2.326 years.
Step-by-step explanation:
We have the standard deviation for the sample. So we use the t-distribution to solve this question.
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 2.326/tex]Now, find the width of the interval[tex]W = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=z%20%3D%202.326%2Ftex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3ENow%3C%2Fstrong%3E%2C%20find%20the%20width%20of%20the%20interval%3C%2Fp%3E%3Cp%3E%5Btex%5DW%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
In this question:

So


The correct answer is:
C. ± 2.326 years.
Answer:
0.143
Step-by-step explanation:
You need to convert 1/7 to have a denominator of either 100 or 10. We can do 100.
1/7 = ?/100
then you need to divide 100/7 to find the scale factor which in this case is 14.286
then you can insert it into the equation
1/7 = 1 * 14.286/100
you end up with
14.286/100
then you can dived the two
0.14286 is what you end up with
but since it says rounded to the 3rd decimal place you go to the 3rd which is 2.
To round it you look at the 4th number which is 8.
<em>5 and above give it a shove up</em>
So now its 0.143
Hope this helped :)
Answer:

Explanation:
<u>Given Expression</u>:
Use the Quadratic Formula:

<u>insert coefficients</u>





I think the answer is 18.8 Miles/gallons. 325.4 miles / 17.3 gallons = 18.78 miles/gallons, round it to 18.8 miles/gallons.
Answer:
2758.653
Step-by-step explanation:
I'm super smart