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Setler [38]
3 years ago
8

How can I solve number 4 and 6?

Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0
4. Here you would use the Pythagorean Theorem. a² + b² = c²
In this case a and b are the same, so : a² + a² = c² would also work.
a = 5√2 so: (5√2)² + (5√2)² = c²
Do you know where to go from here?
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Instructions: Given the following constraints, find the maximum and minimum values for z.
loris [4]

Answer:

x+3y\leq 0        

x-y\geq 0

1) x+3y=0

x-y=0

-----

4y=0

y=0

x=0

(0,0)

2)(x+3y=0)3

3x-7y=16

3x+9y=0

3x-7y=16\\------\\16y=-16

y=-1

(3,-1)

3)(x-y=0)3

3x-7y=16

3x-3y=16

3x-3y=0

3x-7y=16\\------\\4y=-16

y=-4

x=4

(4,-4)

Z=-x+5y

(0,0):z=0

(3,-1):z=-8

(4,-4):z=-24

Maximum \:Value\: of\: z:0

Minimum\: Value\: of\: z:-24

<u>OAmalOHopeO</u>

8 0
3 years ago
Identify the segment bisector of MN Then find MN.<br> ????????? Helppp pleaseee
enot [183]

Given:

The figure.

To find:

The segment bisector of MN and value of MN.

Solution:

From the given figure it is clear that ray RP,i.e., \overrightarrow {RP} is the segment bisector of MN because it divides segment MN in two equal parts.

Now,

3\dfrac{5}{6}=\dfrac{3\times 6+5}{6}

3\dfrac{5}{6}=\dfrac{23}{6}

Since, \overrightarrow {RP} is the segment bisector of MN, therefore,

MN=2\times \dfrac{23}{6}

MN=\dfrac{23}{3}

MN=7\dfrac{2}{3}

Therefore, the length of MN is 7\dfrac{2}{3}.

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Rearrange the first inequality to match the second inequality and fill in the blanks for the variables. Then select the appropri
balandron [24]

Answer:

The solution set would be all real numbers

Step-by-step explanation:

Remember that you should pass from one side to the other the terms which are similar, that is to say x with x and numbers with numbers. In doing so you must be sure to change the sign of the term if it is passed from one side to the other.

In this case it would be:

4x + 7x + 1 < 11x + 2

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We can see that x is eliminated, because we change the sign on 11 to be -11:

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