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scoray [572]
2 years ago
8

How much cm³ is it the cilinder?

Mathematics
2 answers:
pychu [463]2 years ago
7 0

Answer:

one because it is cilinder

Liula [17]2 years ago
3 0

Answer:

3619.11 cm^3

Step-by-step explanation:

Volume of a cylinder =   area of end * height

                                   = pi r^2       *   height

                                   = pi (6)^2    *   32      cm^3

                                   = 36 pi    * 32  = 3619.11 cm^3

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s344n2d4d5 [400]

move it 0.25 units right

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What’s the correct answer for this?
Gnesinka [82]

Answer: false

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The sides of an equilateral triangle measure 16 inches. The midpoints of the sides of the triangle are joined to form another eq
Alex Ar [27]

Answer:

  90 inches

Step-by-step explanation:

The perimeter of the inscribed triangle is 1/2 that of the enclosing triangle. So, the total of perimeters is ...

  (3·16 in)(1 +1/2 +1/4 +1/8) = (48 in)(15/8) = 90 inches

5 0
3 years ago
Find the height of the triangle by applying formulas for the area of a triangle and your
Xelga [282]

Answer:

h=2.142

Step-by-step explanation:

Area of triangle(a)=1/2 b* h

Area of scalene traingle(a)=√s(s-a)(s-b)(s-c)

Semi perimeter(s)=(a+b+c)/2=(6+10+14)/2=15 yd

√s(s-a)(s-b)(s-c)=√15(15-6)(15-10)(15-14)=√15*9*5*1=√225=15 yd

Area of triangle(a)=1/2 b* h

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You dont have any of those options so it might a mistake.

6 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
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