Question

Solve for the specified variable: c(a+b)-d=f for a

Answer 1

Answer:

$\large\boxed{a=\dfrac{f+d}{c}-b=\dfrac{f+d-bc}{c}}$

Step-by-step explanation:

$c(a+b)-d=f\qquad\text{add}\ d\ \text{to both sides}\\\\c(a+b)=f+d\qquad\text{divide both sides by }\ c\neq0\\\\a+b=\dfrac{f+d}{c}\qquad\text{subtract}\ b\ \text{from both sides}\\\\a=\dfrac{f+d}{c}-b\\\\a=\dfrac{f+d}{c}-\dfrac{bc}{c}\\\\a=\dfrac{f+d-bc}{c}$

Answer 2

Answer:

a = $\frac{f+d}{c}$ - b

Step-by-step explanation:

Given

c(a + b) - d = f ( add d to both sides )

c(a + b) = f + d ( divide both sides by the multiplier c )

a + b = $\frac{f+d}{c}$ ( subtract b from both sides )

a = $\frac{f+d}{c}$ - b