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Genrish500 [490]
3 years ago
12

Solve for the specified variable: c(a+b)-d=f for a

Mathematics
2 answers:
kifflom [539]3 years ago
8 0

Answer:

\large\boxed{a=\dfrac{f+d}{c}-b=\dfrac{f+d-bc}{c}}

Step-by-step explanation:

c(a+b)-d=f\qquad\text{add}\ d\ \text{to both sides}\\\\c(a+b)=f+d\qquad\text{divide both sides by }\ c\neq0\\\\a+b=\dfrac{f+d}{c}\qquad\text{subtract}\ b\ \text{from both sides}\\\\a=\dfrac{f+d}{c}-b\\\\a=\dfrac{f+d}{c}-\dfrac{bc}{c}\\\\a=\dfrac{f+d-bc}{c}

Dima020 [189]3 years ago
6 0

Answer:

a = \frac{f+d}{c} - b

Step-by-step explanation:

Given

c(a + b) - d = f ( add d to both sides )

c(a + b) = f + d ( divide both sides by the multiplier c )

a + b = \frac{f+d}{c} ( subtract b from both sides )

a = \frac{f+d}{c} - b

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place parentheses in the equation below so that you solve by finding the difference between 28 and 3 Write the answer 4×7-3=
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3 years ago
Help me please with explanation
8_murik_8 [283]

Step-by-step explanation:

angle AOB = x+3

angle AOC = 2x + 11

angle BOC = 4x-7

angle AOC = angle AOB + angle BOC

=> 2x +11 = (x+3) + (4x-7)

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=> 3x = 15

x = 5

subst x = 5 in the given formulas

angle AOB = x +3 =8

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angle BOC = 4x - 7 = 13

7 0
3 years ago
I need the answer,Had to solve for homework and still working on it?
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