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3 years ago

Tan θ sin θ + sin θ = 0 . Solve the given equation.

Mathematics

1 answer:

VashaNatasha [74]3 years ago

4 0

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A toy rocket is launched from a platform that is 48 ft high. The rocket height above the ground is modeled by h=-16t^2+32t+48. a

Komok [63]

Answer:

a) 64 feet

b) 3 seconds

Step-by-step explanation:

The maximum height of $h=h(t)$ can be bound by finding the y-coordinate of the vertex of $y=-16x^2+32x+48$ .

Compare this equation to $y=ax^2+bx+c$ to find the values of $a,b,\text{ and } c$ .

$a=-16$

$b=32$

$c=48$ .

The x-coordinate of the vertex can be found by evaluating:

$\frac{-b}{2a}=\frac{-32}{2(-16)$

$\frac{-b}{2a}=\frac{-32}{-32}$

$\frac{-b}{2a}=1$

So the x-coordinate of the vertex is 1.

The y-coordinate can be found be evaluating $y=-16x^2+32x+48$ at $x=1$ :

$y=-16(1)^2+32(1)+48$

$y=-16+32+48$

$y=16+48$

$y=64$

So the maximum height of the rocket is 64 ft high.

When the rocket hit's the ground the height that the rocket will be from the ground is 0 ft.

So we are trying to find the second t such that:

$0=-16t^2+32t+48$

I'm going to divide both sides by -16:

$0=t^2-2t-3$

Now we need to find two numbers that multiply to be -3 and add to be -2.

Those numbers are -3 and 1 since (-3)(1)=-3 and (-3)+(1)=-2.

$0=(t-3)(t+1)$

This implies we have either $t-3=0$ or $t+1=0$

The first equation can be solved by adding 3 on both sides: $t=3$ .

The second equation can be solved by subtracting 1 on both sides: $t=-1$ .

So when $t=3$ seconds, is when the rocket has hit the ground.

5 0

3 years ago

While shopping for clothes, Curtis spent $33 less than 3 times what Jaclyn spent.Curtis spent $12.Write and solve an equation to

Tema [17]

Answer:

12 x 3 = 36 + 33

Step-by-step explanation:

sorry if it's wrong but the answer to the equation i put out would be 69

7 0

3 years ago

Without graphing, is the system independent, dependent, inconsistent? {12x=3y=12 y=-4x+5

Alla [95]

Okay so you out them into the form of y=mx+b. since equation 2 is already like that you need to do it to equation 1. which is y=-4x+4. graph both equations. if it has a solution (1 point where the two lines meet) it is consistantly and independent. if they are parallel lines and the solution is 0 the system is inconsistent and the lines are dependent. if it's the same line they are consistent and dependent. the line is not the same since the y intercept is different. the slope is the same though which tells us its parallel. so the system has a solution of 0 and is inconsistent and the lines are independent.

7 0

3 years ago

Heather wants to put some bricks around her campfire.

Novosadov [1.4K]

Answer:

ibk looks it up please hope this helps

3 0

2 years ago

A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th

mrs_skeptik [129]

Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.

4 0

3 years ago