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2 years ago

WHO EVER ANSWERS CORRECTLY FIRSRT GETS BRAINLIEST

Mathematics

2 answers:

NARA [144]2 years ago

4 0

Answer:

Total length of the road = 6 3/4 miles.

Each markers are spaced at a distance = 1/8 of a mile.

Step-by-step explanation:

Total length of the road ÷ each marker space =

a) 6 3/4 ÷ 1/8.

b) In order to solve it, we need to convert that fraction into improper fraction:

6 3/4 = 27/4

6 3/4 ÷ 1/8 = 27/4 ÷ 1/8

We need to convert division sign into multiplication sign and flip the second fraction.

27/4 × 8/1

then simplify to get

27 × 2 = 54.

There would be total number of 54 markers of lengths (1/8) of a mile.

Rainbow [258]2 years ago

3 0

I got 54, I might be wrong. I divided 6 3/4 by 1/8

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2 years ago

4(b+24)=(12b+8) pls help

vfiekz [6]

Answer:

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Step-by-step explanation:

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3 years ago

Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x

fredd [130]

Answer:

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

$6\cdot x^{2} \geq 10 + 11\cdot x$

$6\cdot x^{2}-11\cdot x -10 \geq 0$

$6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0$

Roots are found by Quadratic Formula:

$r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}$

$r_{1} = \frac{5}{2}$ and $r_{2} = -\frac{2}{3}$

Then, the factorized form of the inequation is:

$6\cdot \left(x-\frac{5}{2}\right)\cdot \left(x+\frac{2}{3} \right)\geq 0$

By Real Algebra, there are two condition that fulfill the inequation:

a) $x-\frac{5}{2} \geq 0 \,\wedge\,x+\frac{2}{3}\geq 0$

$x \geq \frac{5}{2}\,\wedge\,x \geq-\frac{2}{3}$

$x \geq \frac{5}{2}$

b) $x-\frac{5}{2} \leq 0 \,\wedge\,x+\frac{2}{3}\leq 0$

$x \leq \frac{5}{2}\,\wedge\,x\leq-\frac{2}{3}$

$x\leq -\frac{2}{3}$

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

3 0

3 years ago

A timer is started and a few moments later a swimmer dives into the water and then comes back up. The swimmer’s depth (in feet)

zhannawk [14.2K]

Answer: The swimmer dives into the water 5 seconds after the timer is started.

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Step-by-step explanation:

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1 year ago

using the midpoint formula, solve for the midpoint of the segment with these pairs of endpoints (-11,30) and (-26,-2)

REY [17]

Answer:

Midpoint is $(\frac{-37 }{2}, 14)$

Step-by-step explanation:

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

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Midpoint is (-37/2, 14)

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2 years ago