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weqwewe [10]
3 years ago
15

Kendra was given three gift certificates for her birthday, each worth 333 points, for a music service. In the past Kendra has do

wnloaded five songs and seven videos for a total of 295 points. Another time she downloaded ten songs and three videos for a total of 150. What is the most songs that Kendra can get with her certificates if she doesn’t buy any videos?
Mathematics
1 answer:
Airida [17]3 years ago
5 0
Let x be the number of song points.
Let y be the number of videos points.

We have the first expression:
5x + 7y = 295

We have the second expression:
10x + 3y=150

Solve for y and x:
x = (295 -7y)/5
10 ((295-7y)/5) + 3y  = 150
590 - 14y + 3y =150
590 - 150 = 14y -3y
y=40 points

solving for x:
x = (295-7*40)/5
x=3 points/song

If she buy, all songs for 333 points
number of songs = 333 / 3
number of songs = 111

The answer is 111.
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Seiji and Gavin both worked hard over the summer. Together, they earned a total of $425. Gavin earned $25 more than Seiji. How m
schepotkina [342]
S + g = 425
g = s + 25
-----------------
We will use the method of substitution:
s + s + 25 = 425
2 s = 425 - 25
2 s = 400
s = 400 : 2
s = $425
g = 200 + 25
g = $225
Answer: Seiji earned $200 and Gavin earned $225.
5 0
3 years ago
Are 5(2x-y) and 15x-5y equivalent expressions?
krek1111 [17]

No, they are not equivalent.

5(2x - y) = 10x - 5y and it is not equal to 15x - 5y.

(using distribution property)

6 0
3 years ago
How do I solve this equation: -5/6b + 3/4 = 1/2b - 2/3 ?
Gre4nikov [31]
First get like things on the same side:
-5/6b - 1/2b= -2/3 - 3/4

Then find equivalent fractions to make the equation easier to solve.
-5/6b - 3/6b= -8/12 - 9/12

Then just add things together and solve.
-8/6b= -17/12
-8b= 6(-17/12)
-8b= -17/2
b= (-17/2)/-8
b= 17/16

You can then plug the answer back into the original question to make sure it is the correct answer.
3 0
3 years ago
EXAMPLE 5 If F(x, y, z) = 4y2i + (8xy + 4e4z)j + 16ye4zk, find a function f such that ∇f = F. SOLUTION If there is such a functi
Valentin [98]

If there is such a scalar function <em>f</em>, then

\dfrac{\partial f}{\partial x}=4y^2

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}

\dfrac{\partial f}{\partial z}=16ye^{4z}

Integrate both sides of the first equation with respect to <em>x</em> :

f(x,y,z)=4xy^2+g(y,z)

Differentiate both sides with respect to <em>y</em> :

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}

\implies\dfrac{\partial g}{\partial y}=4e^{4z}

Integrate both sides with respect to <em>y</em> :

g(y,z)=4ye^{4z}+h(z)

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :

f(x,y,z)=4xy^2+4ye^{4z}+h(z)

\dfrac{\partial f}{\partial z}=16ye^{4z}=16ye^{4z}+\dfrac{\mathrm dh}{\mathrm dz}

\implies\dfrac{\mathrm dh}{\mathrm dz}=0

Integrate both sides with respect to <em>z</em> :

h(z)=C

So we end up with

\boxed{f(x,y,z)=4xy^2+4ye^{4z}+C}

7 0
3 years ago
How would I do this problem? In trapezoid PQRS, PQ is parallel to SR. Find the area of PQRS. Leave your answer is simplest radic
Mrac [35]
Can u take its pictures and post it bcuz it might be easer to answer
7 0
3 years ago
Read 2 more answers
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