Complete question :
A 12-foot by 15-foot patio is increased by placing a stone border around the patio. The width of the border is the same all around the patio.The perimeter of the patio after it is expanded is 74 feet. The equation which represents x, the width of the border is 2[(12+2x)+15+2x)]=74. What is the width of the border?
1) 2 1/2 feet
2) 3 feet
4) 5 feet
5) 8 1/2 feet
Answer:
2.5
Step-by-step explanation:
Solving for X in the perimeter equation :
2[(12+2x)+15+2x)]=74
Open the bracket
2[(12 + 2x + 15 + 2x)] = 74
2(27 + 4x) = 74
54 + 8x = 74
8x = 74 - 54
8x = 20
x = 20/8
x = 2.5
Hence, width fo border = 2.5
I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
Answer:

Step-by-step explanation:
so Kennedy is right
Answer:
Rewrite so y is on the left side of the inequality.
−83y>43
Multiply each term by −38 and simplify.
Inequality Form:
y<−1/2
Interval Notation:
(−∞,−1/2)
Step-by-step explanation:
Answer:
degree = 120°
A =67 cm²
d=?
note : diameter= 2×radius
area of a circle = πr²
67=22/7 ×r²
67×7=22r²
469=22r²
r²=469/22
r²=21.32
r=4.62
diameter=2 × radius
d= 2× 4.62
d=9.24
d=9
I hope it helps :)