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3 years ago

(2c^{-5})^{3} simplify

Mathematics

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

Step-by-step explanation:

If this is

$(2c^{-5})^3$ then you distribute the 3 to both terms inside the parenthesis (the 2 and the c^-5). 2 cubed is 8. The rule for the power to power is that you multiply the powers together to get -15. So the final simplification is

$8^{-15}$

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A student expressed the sum of 2 whole numbers as 5 times (8+3).What are the 2 whole numbers?

Marta_Voda [28]

Well if the two numbers are equal to 5x(8+3).

Lets say that these two numbers are X and Y,

So that would be X + Y = 5(8+3)

which means X + Y = 55

You could write that as a fuctions Y = 55 - X

Now by using the graph you get and the X values of [0,55] ( This means every value from 0 to 55 ), you will get a X and Y value that if you added up together will give you the value of 8(5+33)

An examples for the answers would be

(0,55) (1,54) (2,53) (3,52) (4,51) (5,50) (6,49) ... it goes on until x reaches 55.

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2 years ago

Which number line shows the solutions of 13x−8≥x+6?

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3 years ago

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A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found

irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

$H_0: p = 0.04$

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

$H_a: p > 0.04$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that $\mu = 0.04, \sigma = \sqrt{0.04*0.96}$

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that $n = 20, X = 0.1$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}$

$z = 1.37$

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

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Divide x4+2x2−24<br> by x+2

Ipatiy [6.2K]

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$\displaystyle \frac{x^4+2x^2-24}{x+2} =x^3-2x^2+4x-8 -\frac{8}{x+2}$

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3 years ago

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(2c^{-5})^{3} simplify ​

(2c^{-5})^{3} simplify