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3 years ago

Determine the quotient and remainder F(x)=6x^4+12x^3+24x^2+ 23x+18 is divided by g(x)=2x^2+2x+4

1 answer:

8 0

The only way to do this one is by long division which I can't figure out how to show here. There are some great examples online if you google long division with polynomials.

The answer is 3x^2+3x+3 with a remainder of 5x+6 who's is usually shown as (5x+6)/2x^2 +2x+4 which was the divisor g(x).

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PLZZZZZZZ HELP ASAP Figure JKL is reflected about the y-axis to obtain figure J’K’L’: A coordinate plane is shown. Triangle JKL

Ierofanga [76]

Answer:

A i think

Step-by-step explanation:

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3 years ago

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Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

5 0

3 years ago

Find the slope of the line

andrey2020 [161]

Answer:

-2/3x

Step-by-step explanation:

To find the slope, you would do rise/run.

To get to one point to the other, you move 2 units down and 3 to the right.

Hope this helps!

3 0

2 years ago

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Luke paid $12.69 for 3 greeting cards. Each card cost the same amount,

n200080 [17]

3c = 12.69
where c = # of greeting cars

3 0

3 years ago

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Systems of equations and inequalities<br> solving systems by elimination<br> {y= -x+1<br> {y= 4x-14

kodGreya [7K]

Answer:

x = 3 , y = -2

Step-by-step explanation:

Solve the following system:

{y = 1 - x | (equation 1)

y = 4 x - 14 | (equation 2)

Express the system in standard form:

{x + y = 1 | (equation 1)

-(4 x) + y = -14 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -14 | (equation 1)

x + y = 1 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{-(4 x) + y = -14 | (equation 1)

0 x+(5 y)/4 = (-5)/2 | (equation 2)

Multiply equation 2 by 4/5:

{-(4 x) + y = -14 | (equation 1)

0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -12 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 3 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = 3 , y = -2

5 0

3 years ago

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