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<span><span> 5x2-23x=-26</span> </span>Two solutions were found :<span><span> x = 2
</span><span> x = 13/5 = 2.600
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Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
5*x^2-23*x-(-26)=0
Step by step solution :Skip Ad
<span> Step 1 :</span><span>Equation at the end of step 1 :</span><span> (5x2 - 23x) - -26 = 0
</span><span> Step 2 :</span>Trying to factor by splitting the middle term
<span> 2.1 </span> Factoring <span> 5x2-23x+26</span>
The first term is, <span> <span>5x2</span> </span> its coefficient is <span> 5 </span>.
The middle term is, <span> -23x </span> its coefficient is <span> -23 </span>.
The last term, "the constant", is <span> +26 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> 5 • 26 = 130</span>
Step-2 : Find two factors of 130 whose sum equals the coefficient of the middle term, which is <span> -23 </span>.
<span><span>
-130
+
-1
=
-131
<span>
</span>
</span>
<span>
-65
+
-2
=
-67
<span>
</span>
</span>
<span>
-26
+
-5
=
-31
<span>
</span>
</span>
<span>
-13
+
-10
=
-23
That's it</span></span>
We have been given that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each bounce. We are asked to find the total distance traveled by up and down from the time it was dropped from the window until the 25th bounce.
We will use sum of geometric sequence formula to solve our given problem.
, where,
a = First term of sequence,
r = Common ratio,
n = Number of terms.
For our given problem 
, 
and 
.
Therefore, the ball will travel 100 meters and option B is the correct choice.
Answer:
slope is about 1.67
Step-by-step explanation:
2/1.2 ≈ 1.67
hope this helps :)
Answer:
A.
Step-by-step explanation:
Answer:
0.025 grams
Step-by-step explanation:
The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:
Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)
Volume of drained water = 25 x 10⁻⁶ m³
Density of drained water = 1000 kg/m³
So, for the mass of drained water:
Density of drained water = Mass of drained water/Volume of drained water
Mass of drained water = (Density of drained water)(Volume of drained water)
Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)
<u>Mass of drained water = 0.025 gram</u>
Density
