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kolezko [41]
3 years ago
15

What is the sum of X^2-3x+7 and 3x^2+5x-9

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0
X^2 - 3x+7 + 3x^2 + 5x-9
4x^2
-3x+7+5x-9
2x+2
4x^2+2x+2
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I’ll give u brainliest!!<br> what is the area of shape 1, 2 and 3
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Answer:

Shape 1: 25.915

Shape 2: 102.85

Shape 3: 142

Step-by-step explanation:

For shape 1, you have to divide 7.1 to get half the width of the triangle. You get 3.55 from that, and then finding the triangle itself you have to do 7.3*3.55 to get 25.915. For shape 2, you first do the harder parts (the triangles) and since there is two of them we don't need to half the width of each triangle. But first to get the width, we need to do 20-17.4=2.6. But since there are 2 triangles we need to divide that by 2 to get 1.3. Then you multiply that by 5.5 to get the final area of both triangles which is 7.15. Next you simply find the rectangle which is 17.4*5.5=95.7. You add the triangles area to get 102.85. Finally for shape 3 you simply do 7.1*20=142.

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3 years ago
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Cerrena [4.2K]

Answer:

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2 years ago
9. (10x2 + 99x – 5) ÷ (x + 10) =
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Which integer is 90 square closest to?
Agata [3.3K]

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8100/8100

I think this the answer to your question.

Step-by-step explanation:

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3 years ago
HELP!!!!
zimovet [89]

Answer:

37.55\ m

Step-by-step explanation:

we know that

The perimeter of the figure is equal to the perimeter of semicircle plus the perimeter of quarter circle plus two times the length of 2\ m plus two times the length of 5\ m

<u>Find the perimeter of semicircle</u>

we know that

The circumference of a semicircle is equal to

C=\frac{1}{2}\pi D

we have

D=10\ m

substitute

C=\frac{1}{2}\pi(10)=5 \pi\ m

<u>Find the perimeter of a quarter of circle</u>

we know that

The circumference of a quarter of circle is equal to

C=\frac{1}{4}\pi D

we have

D=10\ m

substitute

C=\frac{1}{4}\pi(10)=2.5 \pi\ m

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7.5 \pi+14=37.55\ m

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