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Vladimir79 [104]
4 years ago
8

How to solve this and explain

Mathematics
1 answer:
Goryan [66]4 years ago
5 0
You first wanna find <BAD, because if AB is perpendicular to AC, then it has to form a 90 degree angle. So 90-56=34 degrees. So now you have a 34 & 63 degrees in the ABD triangle. In a triangle, all angles add up to equal 180 degrees. So 34+63+x=180...and x=83. So <ADB= 83 degrees. Now you want to find angle ADC...which you can just subtract 83 from 180 (because <ADB & <ADC forms 180 degree angle). You will then get 97 as angle ADC. So, the same thing as before, add up 56+97+x=180, because all angles (in the triangle ADC) add up to be 180 degrees. X will then equal 27 degrees. Angle ACB= 27 degrees.
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$8.49×6=□<br><br> $509.40<br><br> $50.94<br><br> $50.93<br><br> $5.09
Alex787 [66]
Answer is 50.94 dollars
7 0
3 years ago
Read 2 more answers
The weight of 45 cartons is 405kg. Find the weight of 73 cartons​
vodka [1.7K]

Answer:

657kg

Step-by-step explanation:

405 ÷ 45 = 9

9 x 73 = 657kg

I hope this helps!

8 0
3 years ago
Read 2 more answers
Which number from the set of numbers {3, 5, 6, 7} makes the equation below TRUE?
beks73 [17]

Answer:

6

Step-by-step explanation:

replace x with 6 in the ecuation.

4(6)=24 - 8 =16

5 0
3 years ago
Read 2 more answers
Sketch the region enclosed by y=e3x,y=e5x and x=1. Decide whether to integrate with respect to x or y, and then find the area of
Lina20 [59]

The area of the region is \text { Area } \approx 23.12

Explanation:

The area of the region is given by

\text { Area }=\int_{0}^{1}\left(e^{5 x}-e^{3 x}\right) d x

Integrating the terms inside the bracket, we get,

\left[\frac{e^{5 x}}{5}-\frac{e^{3 x}}{3}\right]

Now, applying the limits for x for the integrated term,

Area=\frac{e^{5}}{5}-\frac{e^{3}}{3}-\frac{e^{0}}{5}+\frac{e^{0}}{3}

Any number to the power of zero is one. Thus, substituting the values, we get,

Area=\frac{e^{5}}{5}-\frac{e^{3}}{3}-\frac{1}{5}+\frac{1}{3}

Adding the like terms,

Area=\frac{e^{5}}{5}-\frac{e^{3}}{3}+\frac{2}{15}

Simplifying the terms, we get,

\text { Area } \approx 23.12

Thus, The area of the region is \text { Area } \approx 23.12

4 0
4 years ago
PLS HELP
Katena32 [7]

Answer:

-30x^2-9x+12  all real numbers

Step-by-step explanation:

f(x) = -6x + 3 and g(x) = 5x + 4

f(x) * g(x) = (-6x + 3) * ( 5x + 4)

FOIL

            = -30x^2 -24x+15x +12

Combine like terms

           =-30x^2-9x+12

The domain is what numbers x can take

There are no restrictions so all real numbers

3 0
3 years ago
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