Find 1/6 of an hour?
1 answer:
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Graph the system of linear inequalities
x + y > 5
- x - y < -5
First we graph x + y >5
Step 1: replace > symbol by = sign
x + y =5
step 2 : Solve the equation for y
x + y =5 (subtract x from both sides)
y = 5 - x
step 3: Now we make a table . plug in some number for x and find out y
x -----> y
-1 -----> 6 ( y=5-x => y=5-(-1)= 6)
0 -----> 5 ( y=5-x => y=5-(0)= 5)
1 -----> 4 ( y=5-x => y=5-(1)= 4)
Step 4: we graph the table.
step 5: Shade the region that satisfies our inequality
x + y > 5. Greater than symbol implies that we shade the graph to the right
Graphing second inequality - x - y < -5
All terms have negative sign . so divide all the terms by -1. When we divide an inequality by -1 its sign changes
- x - y < -5 becomes x + y > 5
Follow the same steps to graph this inequality
After dividing the second equation by -1 , we got the same as the first equation.
So we will get the same graph
Both graphs overlaps
The graph of first and second inequality overlaps
The graph is attached below
Answer:
A hole at x=-4.
Step-by-step explanation:
This is a fraction so we have to worry about division by zero.
The only time we will be dividing by 0 is when x+4 is 0.
Solving the equation
x+4=0 for x:
Subtract 4 on both sides:
x=-4
So there is either a vertical asymptote or a hole at x=-4.
These are the kinds of discontinuities we can have for a rational function.
If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.
If is is a vertical asymptote, x=-4 will make the top NOT zero.
Let's see what -4 for x in x^2+6x+8 gives us:
(-4)^2+6(-4)+8
16+-24+8
-8+8
0
Top and bottom are 0 when x=-4.
Let's see what happens after simplication.
We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.
So what 2 numbers together multiply to be 8 and add up to be 6.
I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.
We we able to cancel out that factor that was giving us x=-4 is a zero.
Therefore there is a hole at x=-4.