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LuckyWell [14K]

3 years ago

9

I'm just doing this to have an even amount of points

1 answer:

kirill [66]3 years ago

6 0

lol I love even numbers too

You might be interested in

2(x +5)=(x-4) ?<br> Step by step

ExtremeBDS [4]

$\text {Hi There! Let's Solve this Problem!}$

$\text {\underline {The First Step is to Simplify}}$

$\text {2*x=2x}\\\text {2*5=10}$

$\text {Your New Problem Is: 2x+10=x-4}$

$\text {\underline {The Next Step is to Subtract x}}$

$\text {2x+10-x=x-4-x}$

$\text {Your New Problem Is: x+10=-4}$

$\text {\underline {The Final Step is to Subtract 10}}$

$\text {x+10-10 (Crosses Out)}\\\text {-4-10}$

$\text {Your Answer Would Be:}$

$\Huge\boxed {x=-14}$

$\text {Best of Luck!}$

7 0

3 years ago

Read 2 more answers

AB and DE are chords that intersect at point F inside circle C as shown. If the measure of arc EA= 50 degrees and the measure of

defon

Answer:

Part 1) $m\angle AFE=55^o$

Part 2) $m\angle EFB=125^o$

Step-by-step explanation:

Part 1) what is the measure of angle AFE

we know that

The measure of the interior angle is the semisum of the arches that comprise it and its opposite.

<u>Note:</u> In this problem the correct measure of arc EA is 40 degrees (see the picture)

so

$m\angle AFE=\frac{1}{2}(arc\ EA+arc\ DB)$

substitute the given values

$m\angle AFE=\frac{1}{2}(40^o+70^o)=55^o$

Part 2) what is the measure of angle EFB?

we know that

$m\angle AFE+m\angle EFB=180^o$ ---> by supplementary angles (form a linear pair)

so

substitute the given value

$55^o+m\angle EFB=180^o$

$m\angle EFB=180^o-55^o=125^o$

8 0

4 years ago

The second term in a geometric sequence is 12. The fourth term in the same sequence is 4/3. What is the common ratio in this seq

aniked [119]

The common ratio in this sequence is 6:2 or 4:3

3 0

3 years ago

Read 2 more answers

Help please !!!!!!!!!!!!!!!!!!!!!!!!

zysi [14]

Answer:

you must make an equation

Step-by-step explanation:

if you make an equation you should get the answer

5 0

3 years ago

Find a formula for the general term an of the sequence assuming the pattern of the first few terms continues.

Elden [556K]

Answer:

Step-by-step explanation:

$\frac{6}{3},~\frac{6}{9}~\frac{6}{27},~\frac{6}{81},~\frac{6}{243}=\frac{6}{3^1},~\frac{6}{3^2},~\frac{6}{3^3},~\frac{6}{3^4},~\frac{6}{3^5}~=>a_n=\frac{6}{3^n}$

6 0

3 years ago