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3 years ago

If

Mathematics

1 answer:

Vitek1552 [10]3 years ago

8 0

Answer:

Given :

→x-y=12

→xy= 3²

Equation formed:

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy$

Step by step explanation:

${(12)}^{2} = {x}^{2} + {y}^{2} - 2 \times 9 \\ 144 + 18 = {x}^{2} + {y}^{2} \\ = 162$

hope it helped you:)

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Can I have help solving for x?:))

zvonat [6]

Answer:

24.8

Step-by-step explanation:

We will have to use trigonometry here to find the value of x. The first thing we can see is that we need to work out the hypotenuse. We need to chose whether to use Sin, Cos or Tan. We do that by look at the sides .

→ 'x' is the hypotenuse

→ 12 is opposite

→ The adjacent is the side that doesn't have a numerical value to we look for a formula triangle without adjacent in it

Tan = Opposite ÷ Adjacent

Sin = Opposite ÷ Hypotenuse

Cos = Adjacent ÷ Hypotenuse

We can see the Sin formula has no adjacent in it so we use that formula. However we want to work out the hypotenuse so we have to rearrange the sin formula to get hypotenuse as the subject so

Sin = Opposite ÷ Hypotenuse

Hypotenuse = Opposite ÷ Sin

→ Let's substitute in the values

Hypotenuse = 12 ÷ Sin(29)

Hypotenuse = 24.7519841

So the value of x is 24.8 to 1 decimal place

6 0

3 years ago

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What is the scientific notation of 42

Aleksandr-060686 [28]

The answer is 7, because you multiply it by 6.

7 0

2 years ago

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Joe can cut and split a cord of firewood in 3 fewer hours than Dwight can. When they work together, it takes them 2 hours. How

aalyn [17]

Answer:

Dwight will take 6 hours to finish the job alone and Joe will take 3 hours to finish the job alone.

Step-by-step explanation:

Let us assume the time taken by Dwight to split a cord of firewood = K hrs

So, the per hour rate of Dwight = $(\frac{1}{K})$

As, Joe uses 3 LESS hours then Dwight.

So, the time taken by Joe to split a cord of firewood = (K- 3) hrs

So, the per hour rate of Joe = $(\frac{1}{K-3})$

Now, when both of them wok together, it takes them 2 hours.

So, the per hour rate of BOTH of them = $(\frac{1}{2})$

⇒ Per hour rate of ( Dwight + Joe) = $(\frac{1}{2} )$

$\implies (\frac{1}{K}) + (\frac{1}{K-3}) = (\frac{1}{2})$

Now, solving for the value of K , we get:

$(\frac{1}{K}) + (\frac{1}{K-3}) = (\frac{1}{2})\\\implies \frac{(K-3) + K}{K (K-3)} = (\frac{1}{2})\\\implies 2(2K -3) = K^2 - 3K\\\implies k^2 - 3K -4K +6 = 0\\\implies K^2 - 7K + 6= 0\\\implies K^2 - 6K - K + 6= 0\\\implies K(K-6) -1(K - 6)= 0\\\implies (K-6)(K-1) = 0$