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3 years ago

What is the product?

Mathematics

2 answers:

elena-s [515]3 years ago

8 0

Answer:

-2

Step-by-step explanation:

When we multiply a scalar by a matrix, every term in the matrix is multiplied by the scalar

2 * -1 = -2

0 0

ale4655 [162]3 years ago

4 0

The third one is the product
2×-1 =-2
2×0=0
ans(-2 0)

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F(x)=|x+3|-1 range and domain

KiRa [710]

Hey there! :)

Answer:

Domain: (-∞, ∞)

Range: [-1, ∞)

Step-by-step explanation:

This is an absolute-value function. (Graphed below) The vertex is at (-3, -1) which consists of the minimum y-value of the function. Therefore:

Domain: (-∞, ∞)

Range: [-1, ∞)

8 0

3 years ago

Use the quadratic function to predict y if x equals 7. y = 2x2 – 3x + 3

zheka24 [161]

Answer:

Step-by-step explanation:

$f(7)=2(7)^{2} -3(7)+3$

$= 2(49)-21+3\\=98-21+3\\=80\\$

7 0

3 years ago

Pls, can someone answer this, Explain, using words and numbers, how to subtract 7x - ( 6x + 13). Remember to include the solutio

Hitman42 [59]

So first you distribute the negative to the 6x and 13 which will flip the sign of both of them to -6x and -13 so take away the parentheses and the equation is now 7x-6x-13. You combine the x’s and you get 1x-13 or x-13

3 0

3 years ago

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

3 years ago

ankoles [38]

We subtract the 17 from the 981 to make the two sides even so it’s easier to calculate, 981 - 17 = 964, then divide that by 2, 964/2 = 482. So your answer is 482.

Would appreciate brainliest!

6 0

3 years ago