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xxTIMURxx [149]
3 years ago
10

The number of retro portable CD players you are prepared to supply to a retail outlet every week is given by the formula q = 0.2

p^2 + 2p where p is the price it offers you. The retail outlet is currently offering you $70 per CD player. If the price it offers decreases at a rate of $1 per week, how will this affect the number you supply?
Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

Decreasing by 30 per week

Step-by-step explanation:

q = 0.2p^2 + 2p

\frac{dq}{dt}=0.4p \frac{dp}{dt} + 2\frac{dp}{dt}

\frac{dq}{dt}=(0.4p + 2)\frac{dp}{dt}

At p=70,  \frac{dp}{dt}=-1

\frac{dq}{dt}=(0.4X70 + 2)(-1)

\frac{dq}{dt}=-30

The number supplied is decreasing by 30 per week.

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I will mark brainliest IF CORRECT
umka2103 [35]

Answer:

1 - (π/6) - (√3/4)

Step-by-step explanation:

First, calculate the area of ABCD. That's just 1*1 = 1 un^{2}

Then, we are told that arcs BD and AC are circular, meaning they are portions of a circle. Therefore, let's redraw this image a little. Look below for the image.

Essentially, what I've done is created an equilateral triangle and two sectors. You may be wondering why the triangle is equilateral. Well, we firstly know it's isosceles because the two original arcs are circular and congruent. Their overlap creates two congruent lines that can be extend from point M to the vertices A and D. These two lines also happen to be radii of the quarter circles because the two sectors have AM AND AD as radii. AM and AD = 1, so AMD is an equilateral triangle.

Draw altitude OD. This is a right angle. Since equilateral triangles are also isosceles triangles, and isosceles triangles have the property of sharing the median to base and altitude to base, we can say that OD = \frac{1}{2} AD = \frac{1}{2}. MD = 1, so this triangle is a 30-60-90 triangle. Why? This is because of the 30º angle converse theorem. The shorter leg is half of the hypotenuse MD, so <OMD is a 30º angle, making <ODM a 60º angle and inevitably <MDC a 30º angle (because <D is a right angle) and <ABM as well because the two sectors are congruent.

Because m<ABM = m<MDC = 30º, these two sectors are 30/360 of the individual circles or 1/12 of the original circles, which have areas of π (because 1^2*π = π). Each is 1/12π, combined they are 1/6π.

The area of the equilateral triangle is √3/8. This is because MO can be calculated, using the 30-60-90 ratios, to be √3/2. (1 * √3/2)/2 = (√3/2)/2 = √3/4; this uses the area of a triangle. Now, time to calculate the shaded area.

The area of the square is 1, the area of the sectors π/6, and the equilateral triangle √3/4. Subtract the equilateral triangle and sectors' areas from the area of the square to be left with the remaining shaded part. 1-(π/6)-(√3/4) is your final answer. To put that a little more cleanly below in the image.

Hope this helps, have a great day.

3 0
2 years ago
Find the distance between (-1,4) and (5,5)​
Allisa [31]

Answer:

csdkb.jacdsmvadsavbdjk.adck.jdsmvd2182943243phr23

Step-by-step explanation:

4 0
3 years ago
What is the slope of 4x+5y= -10
Aleonysh [2.5K]

Answer:

-\frac{4}{5}

Step-by-step explanation:

To find the slope, rearrange the equation to y=mx+b or y=mx+c.

4x+5y=-10

Subtract 4x from both sides:

5y=-10-4x

Divide 5 on both sides:

y=\frac{-10-4x}{5}

y=-\frac{4}{5} x-2

In the equation of y=mx+b/y=mx+c, m will be the slope.

Therefore, the slope is -\frac{4}{5}

6 0
3 years ago
While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at
tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) =  speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)

simplifying the equation, we get

23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)

23(2.8+2.8)/29=2.8^2-x^2

x^2=(2.8)^2-(23*5.6)/29)=3.4

x=\sqrt{3.4}=1.84m/s

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

brainly.com/question/4931057

#SPJ4

4 0
2 years ago
I also need to know what m∠cdb is
Oliga [24]

Answer:

x = 4

m<cdb = 82

Step-by-step explanation:

The exterior angle thm states that the exterior angle of a triangle is equal to the sum of the opposite interior angles:

7x + 2 + 17x = 98

24x + 2 = 98

24x = 96

x = 4

m<cdb =

y + 98 = 180

y = 180 - 98

y = 82

3 0
3 years ago
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