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Angelina_Jolie [31]
3 years ago
8

(07.02 LC)

Mathematics
1 answer:
babymother [125]3 years ago
8 0

Answer:

statement which is true for the equation

Step-by-step explanation:

d. It has infinitely many solutions.

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vovangra [49]
I think the answer is 50
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3 years ago
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The left and right page numbers of an open book are two consecutive integers whose sum is 389.  Find these page numbers
Nadya [2.5K]

Step-by-step explanation:

Maybe the page numbers can be 143 and 246

143 + 246 = 389

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Order these numbers from least to greatest.<br> 1.401, 1.2011, 1.2, 1.41
ira [324]

Answer:

From least to greatest, the correct order is 1.2, 1.2011, 1.401, and 1.41.

Step-by-step explanation:

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I NEED HELP PLZ ( WILL GIVE BRAINLYIST) ( NO LINKS)
AlladinOne [14]

9514 1404 393

Answer:

  66 cm²

Step-by-step explanation:

The area of the polygon is the sum of the areas of the triangle and the rectangle it sits on. The dimensions of the triangle can be found by examining the top/bottom dimensions shown and the left/right dimensions shown.

The width (base) of the triangle is the difference between the lengths of the bottom and top horizontal lines: (12 -9) cm = 3 cm.

The height of the triangle is the difference between the lengths of the left and right sides of the figure: (9 -5) cm = 4 cm.

The dimensions of the rectangle are shown a the bottom and the left sides of the figure.

  triangle area = 1/2bh = 1/2(3 cm)(4 cm) = 6 cm²

  rectangle area = LW = (12 cm)(5 cm) = 60 cm²

Total polygon area = 6 cm² + 60 cm² = 66 cm²

4 0
2 years ago
A random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard
azamat

Answer:

Option C

Step-by-step explanation:

Given that for a  random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard deviation of 320 square feet.

X, the sizes of houses is Normal

Hence sample mean will be normal with

Mean = 1880

and std dev = \frac{320}{\sqrt{20} } \\=71.5542

For 90% confidence interval critical value for t with degree of freedom 19 is

1.328

Confidence interval upper bound

= mean + margin of error

= 1880+1.328*71.55\\=1975

Option C is right

3 0
3 years ago
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