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DaniilM [7]
3 years ago
10

If the point (5,0) is on the graph of a line, is (5,0) the y-intercept of the line? Explain.

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

No (5,0) is not the y-intercept instead it is the x-intercept since it passes trough the x axis instead of the y axis

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when the sum of an unknown number z and twenty two is divided by the same unknown number,the quotient is twelve what is the unkn
Anarel [89]

The unknown number . . . . .  (z)

The sum of the unknown number and 22 . . . . .  (z + 22)

The sum of the unknown number and 22
divided by the same unknown number . . . . . . .  (z + 22) / z

You said that quotient is 12.              (z + 22) / z  =  12

Multiply each side by 'z' :                  (z + 22)       =  12 z

Subtract 'z' from each side:                      22        =  11 z

Divide each side by  11 :                           2         =      z .
   
6 0
3 years ago
Find r if 0=pi/6 rad sector 64m^2
kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is \theta=\dfrac{\pi}{6}.

To find:

The radius or the value of r.

Solution:

Area of a sector is:

A=\dfrac{1}{2}r^2\theta

Where, r is the radius of the circle and \theta is the central angle of the sector in radian.

Putting A=64,\theta=\dfrac{\pi}{6}, we get

64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}

64=\dfrac{\pi}{12}r^2

64\times \dfrac{12}{\pi}=r^2

\dfrac{768}{\pi}=r^2

Taking square root on both sides, we get

\sqrt{\dfrac{768}{\pi}}=r

16\sqrt{\dfrac{3}{\pi}}=r

Therefore, the value of r is 16\sqrt{\dfrac{3}{\pi}} m.

6 0
3 years ago
Consider the following equation. 9x2 − y2 = 6 (a) Find y' by implicit differentiation. y' = (b) Solve the equation explicitly fo
qaws [65]

Answer:

Step-by-step explanation:

Given is an equation in x and y as

9x^2 - y^2 = 6

We use implicit method to differentiate the above equation

18x-2yy'=0

y' = 9x/y

b) to solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ±

We separate the variables as

yy' =9x\\\frac{y^2}{2} =\frac{9x^2}{2} +C\\y^2 =9x^2+2C

Take square root

y=\sqrt{9x^2+2C} \\y=-\sqrt{9x^2+2C}

6 0
3 years ago
7<br> Write an equation of a line<br> with slope of 23 and<br> y-intercept -6.
emmainna [20.7K]

Answer:

y = 23x - 6

Step-by-step explanation:

The formula for line is y =  mx + b

m is the slope, so plug in 23

b is the y intercept, so plug in -6

So it would be y = 23x + (-6), which simpify into y = 23x - 6

6 0
2 years ago
Roman has 415 baseball cards. He gives away
Sergio [31]

Answer:

45

Step-by-step explanation:

3 0
3 years ago
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