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3 years ago

Write the additive and multiplicative inverse of -1/2

Mathematics

2 answers:

stellarik [79]3 years ago

3 0

Answers:

Additive Inverse = 1/2

Multiplicative Inverse = -2

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Explanation:

The additive inverse of x is -x. The two add to 0.

So the additive inverse of -1/2 is 1/2 because -1/2+1/2 = 0.

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The multiplicative inverse of x is 1/x

More thoroughly, the multiplicative inverse of a/b is b/a.

We apply the reciprocal operation here.

That means the multiplicative inverse of -1/2 is -2/1 which simplifies to -2.

We can see that (-1/2)*(-2) = 1

Any nonzero value multiplied with its multiplicative inverse will always result in 1.

11111nata11111 [884]3 years ago

3 0

Answer:

1. Additive Inverse = $\frac{1}{2}$

2. Multiplicative Inverse = -2

Step-by-step explanation:

An "additive inverse" refers to the number that is being added to another number in order to arrive at a sum of zero (0).

The additive inverse of - $\frac{1}{2}$ is $\frac{1}{2}$ because when you add both numbers, the sum is 0.

- $\frac{1}{2}$ + $\frac{1}{2}$ = 0

A "multiplicative inverse" refers to the number that is being multiplied to another number in order to arrive at a product of 1.

The multiplicative inverse of - $\frac{1}{2}$ is -2 because when you multiply both, the product is 1.

- $\frac{1}{2}$ x -2 = 1

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eduard

Answer:

we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

Step-by-step explanation:

Given the expression

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}$

$=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}$

cancel the common factor: 2

$=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}$

cancel the common factor: p

$=\frac{2p+1}{p^2\left(4p^2-1\right)}$

$=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}$

cancel the common factor: 2p+1

$=\frac{1}{p^2\left(2p-1\right)}$

Expanding

$=\frac{1}{2p^3-p^2}$

Thus, we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

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3 years ago

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

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3 years ago

Find an explicit rule for the nth term of the sequence.

taurus [48]

Answer: -4 . 2ⁿ⁻¹

Step-by-step explanation: This is a geometric progression

the nth term is given by arⁿ⁻¹

a = the first term of the sequence

r = common ratio

n= number of terms

for this sequence

a = -4

r = -8/-4 = 2

nth term, an = -4 . 2ⁿ⁻¹

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3 years ago

Which statement compares the two numbers correctly?

slamgirl [31]

Answer:

Step-by-step explanation:

So, we have-

(6 x .1) + (3 x .01) + (2 x .001)

So, we will solve inside of the parenthesis first.

6 x .1 = .6

So, we got that settled next-

3 x .01 = .03

We got that settled last-

2 x .001 = .002

Lastly, we add them all.

.6 + .03 + .002 = .632

Now we compare.

.632 > .629

So, there is your answer!

Hope this helps!

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2 years ago

In your computation, approximate its value as 3.14.

andrey2020 [161]

Answer: d

Step-by-step explanation:

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$A=l*w\\A=(15in)(12in)\\A=180in^2$

Find the area of the base of the semicircle.

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12 in would be the diameter, divide by 2 to get the radius.

$\frac{12}{2}=6$

Plug this into the formula.

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Since we do not have a full circle but a semi one instead, we must divide our result by 2.

$\frac{113.04}{2}=56.52in^2$

Add both areas.

180+56.52=236.52 $in^2$

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3 years ago

Write the additive and multiplicative inverse of -1/2​

Write the additive and multiplicative inverse of -1/2