I wrote the domain and range in interval notation, not sure if that’s how you’re asked to do it. This is how I was taught to state the domain/range of a graph.
Answer:
no solution
Step-by-step explanation:
1/3(12-6x)=4-2x
4-1.3x=4-2x
4=4-0.7x
0=0.7x
ns
The two numbers are <u>12 and 51.</u>
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EXPLANATION</h3>
To solve this, I did 63-15, to get 48.
I then divided this by 4, to get the first number, which is <u>12.</u>
To find the second answer, I multiplied 12 by 3, which is 36, and then added the 15 back on, to get <u>51.</u>
<u>51 + 12 = </u><em><u>63</u></em>
You distribute -4 to each in the parentheses then you get -24 - 4b = 4 then you add 24 on both sides and get -4b = 28 then you divide each side by -4 and it equals -7
Given:
Replace f(x) by f(x - h).
To find:
The effect on the graph of replacing f(x) by f(x - h).
Solution:
Horizontal shift is defined as:
If the graph f(x) shifts h units left, then f(x+h).
If the graph f(x) shifts h units right, then f(x-h).
Where, h is a constant that represents the horizontal shift.
In the given problem f(x) is replaced by f(x - h) and we need to find the effect on the graph.
Here, we have x-h in place of x.
Therefore, the graph of f(x) shifts h units right to get the graph of f(x-h).
