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2 years ago

Examples of properties communative, associative, and identity?

Mathematics

2 answers:

Stella [2.4K]2 years ago

6 0

Commutative 3+4=4+3

Associative (1+2)+3= 1+(2+3)

Identity x+0=x

BlackZzzverrR [31]2 years ago

3 0

Answer:

Communative: 12 x 5= 5 x 12 Associative: (5) + 6 = (8) + 3 Identity: 5 x 1= 5

Step-by-step explanation:

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Can someone please help me with 44. And 45?

Angelina_Jolie [31]

Problem 44

The term "bisect" means "cut in half".

Since BD bisects angle ABC, this means the smaller angles ABD and DBC are congruent.

angle ABD = angle DBC

x+15 = 4x-45

15+45 = 4x-x

60 = 3x

3x = 60

x = 60/3

x = 20

<h3>Answer: x = 20</h3>

========================================================

Problem 45

We use the same idea as the previous problem

angle ABD = angle DBC

2x+35 = 5x-22

35+22 = 5x-2x

57 = 3x

3x = 57

x = 57/3

x = 19

<h3>Answer: x = 19</h3>

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2 years ago

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How to add 4/12 and 1 2/3

kolbaska11 [484]

Answer:

1 3/5

Step-by-step explanation: First you have to line the fractions up then you add what is under the 1 which is nothing then you add 2 and 4 and get 6 then you add 12 and 3 and get 15 then it can be simplified then you get 1 3/5

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2 years ago

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A recipe calls for 3 cups of sugar and 9 cups of water. How many cups of water should be used with 12 cups of sugar?

Yuki888 [10]

Answer:

Step-by-step explanation:

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2 years ago

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What number is 80% of 80?

gtnhenbr [62]

Answer:

64 IS THE ANSWER........

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2 years ago

What two rational expressions sum to 3x+4/x^2-6x+5?

Lubov Fominskaja [6]

Answer:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

Step-by-step explanation:

The given rational expression is:

$\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}$

We can use concept of Partial Fractions to solve this problem. Let,

$\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}$

Multiplying both sides by (x - 1)(x - 5), we get:

$3x+4=A(x-5)+B(x-1)$

Substituting x = 5, we get:

$3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}$

Substituting x = 1, we get:

$3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}$

Substituting the value of A and B, back in the original equation, we get:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

4 0

2 years ago