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PtichkaEL [24]
3 years ago
13

I'm confused on #21. It's very hard. I tried starting it but I gave up.

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0
Can't read the full question
slamgirl [31]3 years ago
6 0
What is the rest of the question
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How many faces,edges and vertices does a hexagonal pyramid have?
Svetradugi [14.3K]
There are 7 faces, 12 edges and 24 vertices in a hexagonal pyramid.
6 0
3 years ago
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MATH show you work pleaseee i really need this.
dlinn [17]

Answer:

The answer for 1 is B and the answer for 2 is A

Step-by-step explanation:

Because 8-5=3 and 3/3=1 And for 2 -4x6= -24 + 29 = 5

Hope it helps! ^w^

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3 years ago
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Determine whether the statement below is always, sometimes, or never true. two lines with positive slopes are parallel.
elena-s [515]
Always because according to my calculations 
8 0
3 years ago
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Hey everyone !
zhuklara [117]

Answer:

The measure of the largest angle is 120°

Step-by-step explanation:

<em>Lets explain how to find the measure of an angle from the length of the </em>

<em>sides of the triangle</em>

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

 to angle A is BC , the side opposite to angle B is AC and the side

 opposite to angle C is AB, So to find measure of angle A use the rule

 cos(A)=\frac{(AB)^{2}+(AC)^{2}-(BC)^{2}}{2(AB)(AC)}

<em>Lets solve the problem</em>

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

 AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above

∴ cos(C)=\frac{(AC)^{2}+(BC)^{2}-(AB)^{2}}{2(AC)(BC)}

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm

∴ cos(C)=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}

∴ cos(C)=\frac{36+100-196}{120}

∴ cos(C)=\frac{-60}{120}=-0.5

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C = cos^{-1}(-0.5)=120

* <em>The measure of the largest angle is 120°</em>

8 0
3 years ago
Read 2 more answers
The Length of a standard jewel case is 7cm more than its width. The area of the rectangular top of the case is 408cm. Find the l
salantis [7]

Answer:

The length of the case is 24 cm and its width is 17cm.

Step-by-step explanation:

The Length of a standard jewel case is 7cm more than its width.

Let the length be represented by L and the width be represented by W, this means that:

L = 7 + W

The area of the rectangular top of the case is 408cm². The area od a rectangle is given as:

A = L * W

Since L = 7 + W:

A = (7 + W) * W = 7W + W²

The area is 408 cm², hence:

408 = 7W + W²

Solving this as a quadratic equation:

=> W² + 7W - 408 = 0

W² + 24W - 17W - 408 = 0

W(W + 24) - 17(W + 24) = 0

(W - 17) (W + 24) = 0

=> W = 17cm or -24 cm

Since width cannot be negative, the width of the case is 17 cm.

Hence, the length, L, is:

L = 7 + 17 = 24cm.

The length of the case is 24 cm and its width is 17cm.

4 0
3 years ago
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