Answer:

Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

Plug -2 for one of the slopes.

Divide by -2 to find the slope of our line.

Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

Simplify and distribute:

Subtract 4 from both sides:

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
Answer:
x= 1
Step-by-step explanation:
2x1=2+3=5
Answer:
C. 92 degrees
Step-by-step explanation:
Given that the
92° which is one of the angles of the quadrilateral WXYZ
The quadrilateral is first rotated by 270° about the origin and then translated 2 units up, the new position of the quadrilateral is W'X'Y'Z'.
The shape of the quadrilateral is remained unchanged due to rotation and translation, so all the angles of the final quadrilateral W'X'Y'Z' is the same as the angles of the given quadrilateral WXYZ.
So,
By using the given value,
92°
Hence, option (C) is correct.
24ft is the hypotenuse, at an angle of 75<span>⁰, and we need to find the adjacent.
We use cos(), which is adjacent divided by hypotenuse.
Therefore, we can find the adjacent by doing:
25 * cos(75) = 6.47ft
Round the answer however you like.</span>