How many solutions does the system formed by x-y=3 and ay-ax+3a=0 have for a nonzero number a? Explain.
1 answer:
There's no solution that is nonzero. x-y=3 x = 3+y Substitute that to the second equation. ay-a(3+y)+3a=0 6a=0 a=0 y = x-3 Substitute that to the second equation a(x-3)-ax+3a=0 0 = 0
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