All categories

3 years ago

In 2005 USC beat UCLA by 47 points. Together the two teams scored a total of 85 points. Give the final sore of this game

Mathematics

2 answers:

satela [25.4K]3 years ago

6 0

The final score is 38. I got that answer by taking the total amount and subtracting the total score from the other game.

11Alexandr11 [23.1K]3 years ago

4 0

The final score would be USC 66, UCLA 18.

66+18=85. 66-18=47.

You might be interested in

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

5 0

3 years ago

Find the limit (if it exists). (If an answer does not exist, enter DNE.) lim x→(−1/2)+ 6x2 + x − 1 4x2 − 4x − 3

Evgesh-ka [11]

You might be able to do direct substitution.

5 0

2 years ago

Find the surface area of the cylinder to the nearest whole number. The figure is not drawn to

Anettt [7]

Answer:

correct option is 2187

Total surface area is 2,185.44 square inches.

lateral surface area is 640.56 square inches

Step-by-step explanation:

Given

radius of cylinder = 12 inches

height of cylinder = 17 inches

we will us value of pi as 3.14

surface area for cylinder consist of two part

1. lateral surface area which is gven by $2\pi rl$

where r is radius of cylinder and l is height of cylinder

Thus, lateral surface area for given cylinder is

$2\pi rl\\ =>2* 3.14*12*17\\=> 1281.12$

Thus, lateral surface area for given cylinder is 1281.12 square inches.

_________________________________

second part of surface area is area of two base (upper and lower) of cylinder.

area of base is given by area of circle $\pi r^2$

$area \ of \base = \pi r^2 = 3.14*12^2\\=>area \ of \base = 3.14*144 = 452.16$

This, area of base is for one base of cylinder

since there are 2 base

area of both base will be = 2* area of one base

= 2*452.16 = 904.32.

Thus, area of base is 904.32 sq. in.

_______________________________________

Total surface area of cylinder = area of two base+ lateral surface area of cylinder = 1281.12 square inches + 904.32 square inches

= 2,185.44 square inches.

Thus, total surface area is 2,185.44 square inches.

lateral surface area is 640.56 square inches

but option which is closest to calculated value is 2187.

Thus, correct option is 2187

___________________________________________

Note: this problem can be directly solved using formula

total surface area for cylinder = $2\pi r^2 + 2\pi rl$

5 0

2 years ago

Find the vertex of: y=6(x-1)2-8<br> (x,y)

Pepsi [2]

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\begin{array}{lllcll}
y=&6(x-&1)^2&-8\\
&\uparrow &\uparrow &\uparrow \\
&a&h&k
\end{array}$

5 0

2 years ago

-1/2 x -1/7 I do not understand how to do this

Firdavs [7]

Answer:

sss

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers