Answer:
yes
Step-by-step explanation:
Answer:
0 < x ≤ 12 and 0 < y ≤ 36
Step-by-step explanation:
Here, x represents the number of female gazelles and y represents the number of male gazelles.
The zoo only has room for 12 female gazelles.
∵ The number of rooms must be more than or equal to the total female gazelles ,
12 ≥ x
Also, number of animals can not be negative,
And, it must be greater than 0.
⇒ 0 < x ≤ 12,
⇒ 3(0) < 3x ≤ 3(12)
⇒ 0 < 3x ≤ 36
∵ Number of males gazelles = 3 × number of female gazelles
⇒ y = 3x
⇒ 0 < y ≤ 36
Hence, the constraints to represent a thriving population of gazelles at the zoo are,
0 < x ≤ 12,
0 < y ≤ 36
I hope this helps you
COS28=15/17
I think it D cause 30(cos(30x)+14=-16
Your dividing by 30
your 180 (which is degrees) is
radians. As the cosine function is periodic with period 2 we get
We know that:
Profit = Revenue - Cost
Let us say x number of candies are made per week.
Finding Cost per week:
Cost of making 1 bar = 0.15
Cost of making x bars = 0.15x
Fixed rate of making candies per week = 600
Total cost of making x candies per week = 600 + 0.15x
Now let us find Revenue:
Selling price of each bar = 1.50
Selling price of x bars = 1.50x
Now we have to find profit,
Profit = Revenue - Cost
In order to have profit Revenue - Cost >0
So plugging values of revenue and cost to get number of candies,




x>444.44
Rounding off
x>444
Answer: The company must sell greater than 444 candies in order to make profit.