Find the sum or difference of the polynomials (x2−xy+y2) − (x2+xy+y2)

EDIT// answer below thank for the help -.-

HACTEHA [7]

Step-by-step explanation:

Move it it up 4 and then find your x intercepts.

Find the x intercepts.

$-x^2 + 4 = 0$

Move the 4 over to the right

$-x^2 = -4$

Divide out the -

$\frac{-x^2}{-} = \frac{-4}{-}$

$x^2 = 4$

Take the square root of each side

$\sqrt{x^2} = \pm \sqrt{4}$

$x = \pm \sqrt 2$

Our x intercepts are at (-2,0) (2,0)

8 0

3 years ago

Which graph represents 2(cos(2 pi/3)+isin(2 pi/3))?

Artyom0805 [142]

Answer:The one with -1. B

It was D on mine tho so check the graph

Step-by-step explanation:

I got it right on edg

7 0

2 years ago

Read 2 more answers

Match the systems of linear equations with their solutions.

OleMash [197]

Answer:

The solutions of linear equations in the procedure

Step-by-step explanation:

Part 1) we have

x+y=-1 ----> equation A

-6x+2y=14 ----> equation B

Solve the system by elimination

Multiply the equation A by 6 both sides

6*(x+y)=-1*6

6x+6y=-6 -----> equation C

Adds equation C and equation B

6x+6y=-6

-6x+2y=14

-------------------

6y+2y=-6+14

8y=8

y=1

Find the value of x

substitute in the equation A

x+y=-1 ------> x+1=-1 ------> x=-2

The solution is the point (-2,1)

Part 2) we have

-4x+y=-9 -----> equation A

5x+2y=3 ------> equation B

Solve the system by elimination

Multiply the equation A by -2 both sides

-2*(-4x+y)=-9*(-2)

8x-2y=18 ------> equation C

Adds equation B and equation C

5x+2y=3

8x-2y=18

----------------

5x+8x=3+18

13x=21

x=21/13

Find the value of y

substitute in the equation A

-4x+y=-9 ------> -4(21/13)+y=-9 ----> y=-9+84/13 -----> y=-33/13

The solution is the point (21/13,-33/13)

Part 3) we have

-x+2y=4 ------> equation A

-3x+6y=11 -----> equation B

Multiply the equation A by 3 both sides

3*(-x+2y)=4*3 ------> -3x+6y=12

so

Line A and Line B are parallel lines with different y-intercept

therefore

The system has no solution

Part 4) we have

x-2y=-5 -----> equation A

5x+3y=27 ----> equation B

Solve the system by elimination

Multiply the equation A by -5 both sides

-5*(x-2y)=-5*(-5)

-5x+10y=25 -----> equation C

Adds equation B and equation C

5x+3y=27

-5x+10y=25

-------------------

3y+10y=27+25

13y=52

y=4

Find the value of x

Substitute in the equation A

x-2y=-5 -----> x-2(4)=-5 -----> x=-5+8 ------> x=3

The solution is the point (3,4)

Part 5) we have

6x+3y=-6 ------> equation A

2x+y=-2 ------> equation B

Multiply the equation B by 3 both sides

3*(2x+y)=-2*3

6x+3y=6

so

Line A and Line B is the same line

therefore

The system has infinite solutions

Part 6) we have

-7x+y=1 ------> equation A

14x-7y=28 -----> equation B

Solve the system by elimination

Multiply the equation A by 7 both sides

7*(-7x+y)=1*7

-49x+7y=7 -----> equation C

Adds equation B and equation C

14x-7y=28

-49x+7y=7

------------------

14x-49x=28+7

-35x=35

x=-1

Find the value of y

substitute in the equation A

-7x+y=1 -----> -7(-1)+y=1 ----> y=1-7 ----> y=-6

The solution is the point (-1,-6)

6 0

2 years ago

I need help i don't like math lol

Dvinal [7]

Lines m and n are parallel.
Lines k and l are parallel.
Hope this helps :)

3 0

2 years ago

Read 2 more answers

Seorang ayah memberikan sebuah tantangan kepada anaknya untuk i menghitung jumlah uang koin yang diperlukan untuk memenuhi papan

VashaNatasha [74]

The total number of coins required to fill all the $64$ boxes are $\boxed{\bf 18446744073709551615}$ .

Further explanation:

In a chessboard there are $64$ boxes.

The objective is to determine the total number of coins required to fill the $64$ boxes in chessboard.

In the question it is given that in the first box there is $1$ coin, in the second box there are $2$ coins, in the third box there are $8$ coins and it continues so on.

A sequence is formed for the number of coins in different boxes.

The sequence formed for the number of coins in different boxes is as follows:

$\boxed{1,2,4,8,...}$

The above sequence can also be represented as shown below,

$\boxed{2^{0},2^{1},2^{2},2^{3},...}$

It is observed that the above sequence is a geometric sequence.

A geometric sequence is a sequence in which the common ratio between each successive term and the previous term are equal.

The common ratio $(r)$ for the sequence is calculated as follows:

$\begin{aligned}r&=\dfrac{2^{1}}{2^{0}}\\&=2\end{aligned}$

The $n^{th}$ term of a geometric sequence is expressed as follows:

$\boxed{a_{n}=ar^{n-1}}$

In the above equation $a$ is the first term of the sequence and $r$ is the common ratio.

The value of $a$ and $r$ is as follows:

$\boxed{\begin{aligned}a&=1\\r&=2\end{aligned}}$

Since, the total number of boxes are $64$ so, the total number of terms in the sequence is $64$ .

To obtain the number of coins which are required to fill the $64$ boxes we need to find the sum of sequence formed as above.

The sum of $n$ terms of a geometric sequence is calculated as follows:

$\boxed{S_{n}=a\left(\dfrac{r^{n}-1}{r-1}\right)}$

To obtain the sum of the sequence substitute $64$ for $n$ , $1$ for $a$ and $2$ for $r$ in the above equation.

$\begin{aligned}S_{n}&=1\left(\dfrac{2^{64}-1}{2-1}\right)\\&=\dfrac{18446744073709551616-1}{1}\\&=18446744073709551615\end{aligned}$

Therefore, the total number of coins required to fill all the $64$ boxes are $\boxed{\bf 18446744073709551615}$ .

Learn more:

1. A problem on greatest integer function brainly.com/question/8243712

2. A problem to find radius and center of circle brainly.com/question/9510228

3. A problem to determine intercepts of a line brainly.com/question/1332667

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Sequence

Keywords: Series, sequence, logic, groups, next term, successive term, mathematics, critical thinking, numbers, addition, subtraction, pattern, rule., geometric sequence, common ratio, nth term.

3 0

2 years ago