Find the sum or difference of the polynomials (x2−xy+y2) − (x2+xy+y2)
1 answer:
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A = 480
W = x
L = 11/5*x
therefore 480 = 11/5*x*x
480 = 11/5x^2
480*5 = 11x^2
2400/11 = x^2
However we can't have a negative width so width is
Sub this into the length equation to find length
W = x
L = 11/5*x
therefore 480 = 11/5*x*x
480 = 11/5x^2
480*5 = 11x^2
2400/11 = x^2
However we can't have a negative width so width is
Sub this into the length equation to find length
If cot θ = 12/5, then tan θ = 5/12.
If sec θ = -13/5, then cos θ = -5/13
For tan θ to be positive while cos θ is negative, the quadrant is 3.
The figure below shows θ graphed as a reference angle in quadrant 3.
Answer:
The statement that θ is in quadrant 4 is FALSE.
If sec θ = -13/5, then cos θ = -5/13
For tan θ to be positive while cos θ is negative, the quadrant is 3.
The figure below shows θ graphed as a reference angle in quadrant 3.
Answer:
The statement that θ is in quadrant 4 is FALSE.