Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
Can you take a pic of the problem?
Answer:4/10
Step-by-step explanation:4 shaded in 10 in all
4 out of 10 are shaded = 4/10
Answer:
The answer is 1
Step-by-step explanation: