Solution-

Equating the denominator to 0,
⇒ (x+3)(x+1) = 0
⇒ x= -3, -1
∴ Discontinuities of the function f(x) is at -3, -1
As (x+3) is also a factor of the numerator, you will have what's called a removable discontinuity. That will show up as a hole in the graph.
∴ At x = -3, you will have removable discontinuity.
Answer:
198
Step-by-step explanation:
t20=a+19d.......1
t40=a+39d.......2
t2=a+d=2.........3
According to ques,
t40-t20=a+39d-(a+19d)=40
or,20d=40
or,d=2
Now ,putting the value of d in equation 3,we get,
a=0
t100=a+99d
=0+99×2
=198
It would be: 9m - 5m + 2
= 4m + 2
Hope this helps!
Answer:

Step-by-step explanation:
