What is the solutionto the linear equation? d-10-2d+7=8+d-10-3d

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

3 0

Answer:

Step-by-step explanation:

$d-10-2d+7=8+d-10-3d\qquad\text{combine like terms}\\\\(d-2d)+(-10+7)=(d-3d)+(8-10)\\\\-d-3=-2d-2\qquad\text{add 3 to both sides}\\\\-d=-2d+1\qquad\text{add}\ 2d\ \text{to both sides}\\\\d=1$

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Solve the radical equation x – 7 = square root of -4x+28. Which statement is true about the solutions to the radical equation? T

Julli [10]

Answer:

x = 3 and 7

There are two true solutions.

Step-by-step explanation:

To solve $x-7 = \sqrt{-4x+28}$ , use inverse operations by squaring both sides of the equal sign.

$(x-7)^2 = (\sqrt{-4x+28})^2\\x^2-14x+49 = -4x+28\\x^2-14x+4x+49-28 = 0\\x^2-10x+21=0$

The quadratic expression can be factored into binomials and set equal to 0 by the zero product property to find x.

(x - 3) ( x - 7) = 0

x-3 = 0 so x=3

x-7 = 0 so x=7

Now check each solution into the original equation to be sure it solve the solution and is not extraneous.

$7-7 = \sqrt{-4(7)+28}\\ 0=0$

and

$3-7 = \sqrt{-4(3)+28}\\[tex]-4 = \sqrt{16}\\-4 =-4$ [/tex]

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3 years ago

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nadya68 [22]

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c = ...
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Class A has 25 pupils and class B has 28 pupils. Both classes sit the same maths test. The mean score for class A is 69. The mea

il63 [147K]

Answer:

Step-by-step explanation:

Mean would mean average, which in this case is $\frac{x+y}{2}$